I need to send a POST request to a web server which includes a gzipped request parameter. I'm using Apache HttpClient and I've read that it supports Gzip out of the box, but I can't find any examples of how to do what I need. I'd appreciate it if anyone could post some examples of this.
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Can you be more specific please? What exactly is "a gzipped string"? A gzipped request parameter? Or a gzipped request body? Does your server support gzipped requests? (not all do...) The HttpClient transparent GZIP support which you're reading about concerns HTTP responses, not HTTP requests. – BalusC Aug 22 '11 at 20:56
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Oh, HTTPLib and HttpClient are different libraries... – BalusC Aug 22 '11 at 20:58
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I've edited my question. I meant HttpClient and a gzipped request parameter. Thanks. – Alex Bliskovsky Aug 22 '11 at 21:13
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Just a single gzipped parameter, not the entire request body? How would you send it? As a Base64-encoded parameter value or as a `multipart/form-data` part? Are you sure that the target server can handle this? What exactly is the server expecting? Or is the server code under your full control as well? – BalusC Aug 22 '11 at 21:16
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This would be as part of a `multipart/form-data` request. The server expects a gzipped parameter. – Alex Bliskovsky Aug 22 '11 at 21:19
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OK, what's the original type of this part value? A `String`? A `File`? Etc. – BalusC Aug 22 '11 at 21:28
2 Answers
19
You need to turn that String
into a gzipped byte[]
or (temp) File
first. Let's assume that it's not an extraordinary large String
value so that a byte[]
is safe enough for the available JVM memory:
String foo = "value";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
try (GZIPOutputStream gzos = new GZIPOutputStream(baos)) {
gzos.write(foo.getBytes("UTF-8"));
}
byte[] fooGzippedBytes = baos.toByteArray();
Then, you can send it as a multipart body using HttpClient as follows:
MultipartEntity entity = new MultipartEntity();
entity.addPart("foo", new InputStreamBody(new ByteArrayInputStream(fooGzippedBytes), "foo.txt"));
HttpPost post = new HttpPost("http://example.com/some");
post.setEntity(entity);
HttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(post);
// ...
Note that HttpClient 4.1 supports the new ByteArrayBody
which can be used as follows:
entity.addPart("foo", new ByteArrayBody(fooGzippedBytes, "foo.txt"));

BalusC
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1If you were to assume the data `POST`ed had the potent of being huge, how could it be done using HTTPClient? I am currently having `out of memory` issues on low VM heap (16MB) devices. – HGPB Mar 14 '13 at 15:42
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This is a good answer, but I'm still going to complain about how a one-line operation takes 20 lines of code using the most standard Java library. – djechlin Jan 14 '14 at 19:45
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@HGPB You would need chunked request with multipart enabled. This will avoid throwing out of memory. – Arun George Mar 23 '17 at 08:55
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Try the GzipCompressingEntity class. If I'm zipping the body of a post e.g. for a JSON object I would go:
// json payload
if (jsonBody != null) {
post.setHeader("Content-Type", "application/json");
StringEntity requestEntity = new StringEntity( jsonBody, ContentType.APPLICATION_JSON);
if (gzipBody) {
GzipCompressingEntity gzippedEntity = new GzipCompressingEntity(requestEntity);
post.setEntity(gzippedEntity);
}else {
post.setEntity(requestEntity);
}
}
Haven't tested but I assume for adding parameters you'd do:
// add parameters
if (parameters != null && parameters.length > 0){
List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
for (int i = 0; i < parameters.length; i++){
urlParameters.add(new BasicNameValuePair(parameters[i][0], parameters[i][1]));
}
post.setEntity(new GzipCompressingEntity(new UrlEncodedFormEntity(urlParameters)));
}

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