Link should be open in same web view in Android

Question

I am new in Android and I am trying to open a Link in webview using this code

WebView myWebView = (WebView) findViewById(R.id.webinfo);
    myWebView.loadUrl("http://oslobokfestival.netteam.no/artical.php?articalid=93");
    myWebView.setBackgroundResource(R.drawable.lbg);
    myWebView.setBackgroundColor(Color.TRANSPARENT);
    myWebView.getSettings().setJavaScriptEnabled(true);

and in this HTML page contains some links and I want that when user click that link should be open in same webview, at this point its opening in mobile browser, please give me appropriate solution.. Thanks.

You can check [this thread](http://stackoverflow.com/questions/6843029/android-webview-new-window-url) which is the same as what you want to do. — Whiler, Sep 05 '11 at 13:46

score 169 · Accepted Answer · edited Jul 21 '17 at 15:36

169

You need to add WebViewClient to your WebView in order to open it in the WebView. Something like

myWebView.setWebViewClient(new WebViewClient() {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
        view.loadUrl(request.getUrl().toString());
        return false;
    }
});

edited Jul 21 '17 at 15:36

Tim

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answered Sep 05 '11 at 13:48

momo

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this works, but is there a way to allow links that have target=_blank applied on them to be opened in new window?? – mim Nov 18 '14 at 12:13
Its working fine but I want to add an icon on external webview – Reaching-Out Apr 21 '16 at 07:35
6

`shouldOverrideUrlLoading(WebView view, String url)` is deprecated and we can use `shouldOverrideUrlLoading(WebView view, WebResourceRequest request)` instead. – Capella Oct 07 '16 at 08:26
getUrl() requires API level 21, So you couldn't run app on some devices. – QMaster Nov 02 '18 at 21:10
6

The documentation says you should not call `view.loadUrl(...)` and instead just return false: "Note: Do not call WebView#loadUrl(String) with the request's URL and then return true. This unnecessarily cancels the current load and starts a new load with the same URL. The correct way to continue loading a given URL is to simply return false, without calling WebView#loadUrl(String)." (https://developer.android.com/reference/android/webkit/WebViewClient#shouldOverrideUrlLoading(android.webkit.WebView,%20android.webkit.WebResourceRequest)) – Lorenz Mar 25 '20 at 21:57

score 14 · Answer 2 · edited Apr 09 '13 at 02:28

14

Try remove @Overrideand an put it after loadurl This work for me...

myWebView.loadUrl("http://someurl.com");
myWebView.setWebViewClient(new WebViewClient() {
    public boolean shouldOverrideUrlLoading(WebView viewx, String urlx) {
        viewx.loadUrl(urlx);
        return false;
    }
});

edited Apr 09 '13 at 02:28

Todd

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answered Apr 09 '13 at 02:09

wsewed

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3

@Overrideand is just annotation to tell your overriding a method, you can (and you should) keep it in there – Srneczek Jan 12 '16 at 19:11

score 5 · Answer 3 · answered Sep 05 '17 at 11:54

For me its works by simply overriding

shouldOverrideUrlLoading methods and

return super.shouldOverrideUrlLoading(view, request)

that will handle all links in same WebView.

webview.setWebViewClient(new WebViewClient(){
      @Override
      public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
         return super.shouldOverrideUrlLoading(view, request);
      }
});

score 1 · Answer 4 · answered Aug 30 '16 at 21:46

Override the method shouldOverrideUrlLoading of WebViewClient like this:

myWebView.setWebViewClient(new WebViewClient(){
        @Override
        public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
            view.loadUrl(request.toString());
            return true;
        }
    });

and add this tag <uses-permission android:name="android.permission.INTERNET" /> in your manifest file To get access to the internet

score 1 · Answer 5 · edited May 29 '18 at 11:36

1

public class MainActivity extends Activity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        WebView webView = (WebView) findViewById(R.id.webView);
        WebSettings webSettings = webView.getSettings();
        webSettings.setJavaScriptEnabled(true);
        webView.loadUrl("#");
    }
}

edited May 29 '18 at 11:36

Nikola Lukic

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answered May 29 '18 at 11:14

Harish Vaishnav

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Nice but put some explanation to make answer more respective ! – Nikola Lukic May 29 '18 at 11:37

score 1 · Answer 6 · answered Jul 27 '21 at 12:22

Here is how to do it kotlin and also take care of the Versions below 21:

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
            myWebView.webViewClient = object : WebViewClient() {
                override fun shouldOverrideUrlLoading(
                    view: WebView,
                    request: WebResourceRequest
                ): Boolean {
                    view.loadUrl(request.url.toString())
                    return false
                }
            }
        } else {
            myWebView.webViewClient = object : WebViewClient() {
                override fun shouldOverrideUrlLoading(view: WebView?, url: String?): Boolean {
                    view?.loadUrl(url.toString())
                    return false
                }
            }
        }

Link should be open in same web view in Android

6 Answers6

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