Yes, it is possible. We can define getters for each index, and return the property value, in the constructor method of the class. See this code.
class className {
constructor() {
this.name = "Bikram";
this.age = 8;
this.x = 89;
this.y = true;
//Use a for loop and define the getters (with the object property's index as its "name") for each property using Object.defineProperty()
for (let i = 0; i < Object.keys(this).length; i++) {
Object.defineProperty(this, i, {
get: function() {
return Object.values(this)[i]}
});
}
}
}
var b = new className();
console.log(b[0]); // same as b.name ("Bikram")
console.log(b[1]); // = b.age (8)
console.log(b[2]); // = b.x (89)
console.log(b[3]); // = b.y (true)
Edit: If you want to change the properties by their indices, which, of course, you do. Then, just define a corresponding setter for each property in the Object.defineProperty() method. It will look like:
// Insert this in place of the old one
Object.defineProperty(this, i, {
get: function() {
return Object.values(this)[i];
},
set: function(newValue) {
this[Object.keys(this)[i]] = newValue;
}
})
console.log(b[0]); // "Bikram"
b[0] = "Bikram Kumar";
console.log(b[0]); // "Bikram Kumar"
And now you have an "array-like-object" whose properties can be accessed or modified either by property key or its index :D
A side note: Notice that Object.keys() and Object.values() only return the enumerable properties. If you just declare a property and not assign it to any value, the Object.[key/value]s() methods will leave that in the returned array, because by default they are not enumerable. This might become confusing for the indices so defined (except the case the undeclared property is the last one).
To get around this, there is a simple way, if you want some property to have a index, but don't wanna assign it now. Just set it to undefined, and it will now be enumerable, and the indices won't be affected.
