What is this date format? 2011-08-12T20:17:46.384Z

Question

I have the following date: 2011-08-12T20:17:46.384Z. What format is this? I'm trying to parse it with Java 1.4 via DateFormat.getDateInstance().parse(dateStr) and I'm getting

java.text.ParseException: Unparseable date: "2011-08-12T20:17:46.384Z"

I think I should be using SimpleDateFormat for parsing, but I have to know the format string first. All I have for that so far is yyyy-MM-dd, because I don't know what the T means in this string--something time zone-related? This date string is coming from the lcmis:downloadedOn tag shown on Files CMIS download history media type.

Answer 1

The T is just a literal to separate the date from the time, and the Z means "zero hour offset" also known as "Zulu time" (UTC). If your strings always have a "Z" you can use:

SimpleDateFormat format = new SimpleDateFormat(
    "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.US);
format.setTimeZone(TimeZone.getTimeZone("UTC"));

Or using Joda Time, you can use ISODateTimeFormat.dateTime().

Answer 2

tl;dr

Standard ISO 8601 format is used by your input string.

Instant.parse ( "2011-08-12T20:17:46.384Z" ) 

ISO 8601

This format is defined by the sensible practical standard, ISO 8601.

The T separates the date portion from the time-of-day portion. The Z on the end means UTC (that is, an offset-from-UTC of zero hours-minutes-seconds). The Z is pronounced “Zulu”.

java.time

The old date-time classes bundled with the earliest versions of Java have proven to be poorly designed, confusing, and troublesome. Avoid them.

Instead, use the java.time framework built into Java 8 and later. The java.time classes supplant both the old date-time classes and the highly successful Joda-Time library.

The java.time classes use ISO 8601 by default when parsing/generating textual representations of date-time values.

The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds. That class can directly parse your input string without bothering to define a formatting pattern.

Instant instant = Instant.parse ( "2011-08-12T20:17:46.384Z" ) ;

---

---

About java.time

The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.

To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.

The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.

You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.* classes. Hibernate 5 & JPA 2.2 support java.time.

Where to obtain the java.time classes?

• Java SE 8, Java SE 9, Java SE 10, Java SE 11, and later - Part of the standard Java API with a bundled implementation.
  • Java 9 brought some minor features and fixes.
• Java SE 6 and Java SE 7
  • Most of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
• Android
  • Later versions of Android (26+) bundle implementations of the java.time classes.
  • For earlier Android (<26), a process known as API desugaring brings a subset of the java.time functionality not originally built into Android.
    • If the desugaring does not offer what you need, the ThreeTenABP project adapts ThreeTen-Backport (mentioned above) to Android. See How to use ThreeTenABP….

Answer 3

Not sure about the Java parsing, but that's ISO8601: http://en.wikipedia.org/wiki/ISO_8601

Answer 4

There are other ways to parse it rather than the first answer. To parse it:

(1) If you want to grab information about date and time, you can parse it to a ZonedDatetime(since Java 8) or Date(old) object:

// ZonedDateTime's default format requires a zone ID(like [Australia/Sydney]) in the end.
// Here, we provide a format which can parse the string correctly.
DateTimeFormatter dtf = DateTimeFormatter.ISO_DATE_TIME;
ZonedDateTime zdt = ZonedDateTime.parse("2011-08-12T20:17:46.384Z", dtf);

or

// 'T' is a literal.
// 'X' is ISO Zone Offset[like +01, -08]; For UTC, it is interpreted as 'Z'(Zero) literal.
String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX";

// since no built-in format, we provides pattern directly.
DateFormat df = new SimpleDateFormat(pattern);

Date myDate = df.parse("2011-08-12T20:17:46.384Z");

(2) If you don't care the date and time and just want to treat the information as a moment in nanoseconds, then you can use Instant:

// The ISO format without zone ID is Instant's default.
// There is no need to pass any format.
Instant ins = Instant.parse("2011-08-12T20:17:46.384Z");

Answer 5

java.time

You do not need DateTimeFormatter to parse the given date-time string.

Java SE 8 Date-Time API(java.time API or the modern Date-Time API) is based on ISO 8601 and does not require using a DateTimeFormatter object explicitly as long as the Date-Time string conforms to the ISO 8601 standards.

The Z in the string is the timezone designator for zero-timezone offset. It stands for Zulu and specifies the Etc/UTC timezone (which has the timezone offset of +00:00 hours).

The T in the string is just the Date-Time separator as per the ISO-8601 standards.

Demo:

import java.time.Instant;
import java.time.OffsetDateTime;
import java.time.ZonedDateTime;

public class Main {
    public static void main(String[] args) {
        String strDateTime = "2011-08-12T20:17:46.384Z";

        Instant instant = Instant.parse(strDateTime);
        OffsetDateTime odt = OffsetDateTime.parse(strDateTime);
        ZonedDateTime zdt = ZonedDateTime.parse(strDateTime);
        
        System.out.println(instant);
        System.out.println(odt);
        System.out.println(zdt);
    }
}

Output:

2011-08-12T20:17:46.384Z
2011-08-12T20:17:46.384Z
2011-08-12T20:17:46.384Z

Learn more about java.time, the modern Date-Time API^* from Trail: Date Time.

The legacy Date-time API

The legacy Date-time API (java.util Date-Time API and their formatting API, SimpleDateFormat) are outdated and error-prone. It is recommended to stop using them completely and switch to the modern Date-Time API^*.

For the sake of completeness, I've written a solution to parse this Date-Time string using the legacy API.

Do not use 'Z' in the pattern with the Date-Time parsing/formatting API.

As already described above, Z (without quotes) is the timezone designator for zero-timezone offset whereas 'Z' is just a character literal and it does not hold any meaning. Use the format, y-M-d'T'H:m:s.SSSXXX. Check the documentation to learn more about these symbols.

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Locale;

public class Main {
    public static void main(String[] args) throws ParseException {
        String strDateTime = "2011-08-12T20:17:46.384Z";

        SimpleDateFormat sdf = new SimpleDateFormat("y-M-d'T'H:m:s.SSSXXX", Locale.ENGLISH);
        Date date = sdf.parse(strDateTime);
        // ...
    }
}

Note that a java.util.Date object is not a real Date-Time object like the modern Date-Time types; rather, it represents the number of milliseconds since the standard base time known as "the epoch", namely January 1, 1970, 00:00:00 GMT (or UTC). Since it does not hold any format and timezone information, it applies the format, EEE MMM dd HH:mm:ss z yyyy and the JVM's timezone to return the value of Date#toString derived from this milliseconds value. If you need to print the Date-Time in a different format and timezone, you will need to use a SimpleDateFormat with the desired format and the applicable timezone e.g.

sdf.setTimeZone(TimeZone.getTimeZone("Etc/UTC"));
String formatted = sdf.format(date);
System.out.println(formatted); // 2011-8-12T20:17:46.384Z

Joda Date-Time API

Quoted below is a notice at the Home Page of Joda-Time:

Note that from Java SE 8 onwards, users are asked to migrate to java.time (JSR-310) - a core part of the JDK which replaces this project.

Again, for the sake of completeness, I've written a solution to parse this Date-Time string using the Joda Date-Time API.

import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;

public class Main {
    public static void main(String[] args) {
        String dateTimeStr = "2011-08-12T20:17:46.384Z";
        DateTimeFormatter dtf = DateTimeFormat.forPattern("y-M-d'T'H:m:s.SSSZ").withOffsetParsed();
        DateTime dateTime = dtf.parseDateTime(dateTimeStr);
        System.out.println(dateTime);
    }
}

Output:

2011-08-12T20:17:46.384Z

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^{* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.}

Answer 6

If you guys are looking for a solution for Android, you can use the following code to get the epoch seconds from the timestamp string.

public static long timestampToEpochSeconds(String srcTimestamp) {
    long epoch = 0;

    try {
        if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.O) {
            Instant instant = Instant.parse(srcTimestamp);
            epoch = instant.getEpochSecond();
        } else {
            SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSSSS'Z'", Locale.getDefault());
            sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
            Date date = sdf.parse(srcTimestamp);
            if (date != null) {
                epoch = date.getTime() / 1000;
            }
        }
    } catch (Exception e) {
        e.printStackTrace();
    }

    return epoch;
}

Sample input: 2019-10-15T05:51:31.537979Z

Sample output: 1571128673

Answer 7

Z represent UTC time zone. With java8+, you can simply use Instant.

public static void main(String[] args) {
    String time = "2022-06-08T04:55:01.000Z";
    System.out.println(Instant.parse(time).toEpochMilli());
}

Answer 8

In JavaScript

let isoDateTimeString = new Date().toISOString();

Description

Date/time format like "YYYY-MM-DDThh:mm:ss.SSSZ" is ISO 8601 date/time format.

Answer 9

You can use the following example.

    String date = "2011-08-12T20:17:46.384Z";

    String inputPattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'";

    String outputPattern = "yyyy-MM-dd HH:mm:ss";

    LocalDateTime inputDate = null;
    String outputDate = null;


    DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern(inputPattern, Locale.ENGLISH);
    DateTimeFormatter outputFormatter = DateTimeFormatter.ofPattern(outputPattern, Locale.ENGLISH);

    inputDate = LocalDateTime.parse(date, inputFormatter);
    outputDate = outputFormatter.format(inputDate);

    System.out.println("inputDate: " + inputDate);
    System.out.println("outputDate: " + outputDate);

Answer 10

FOR JODA TIME

String datetimeString = "2099-12-31T14:20:04Z";
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss'Z'").withZoneUTC();
DateTime dateTime = formatter.parseDateTime(datetimeString);
System.out.println("Parsed date and time: " + dateTime);

Answer 11

This technique translates java.util.Date to UTC format (or any other) and back again.

Define a class like so:

import java.util.Date;

import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;

public class UtcUtility {

public static DateTimeFormatter UTC = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").withZoneUTC();


public static Date parse(DateTimeFormatter dateTimeFormatter, String date) {
    return dateTimeFormatter.parseDateTime(date).toDate();
}

public static String format(DateTimeFormatter dateTimeFormatter, Date date) {
    return format(dateTimeFormatter, date.getTime());
}

private static String format(DateTimeFormatter dateTimeFormatter, long timeInMillis) {
    DateTime dateTime = new DateTime(timeInMillis);
    String formattedString = dateTimeFormatter.print(dateTime);
    return formattedString;
}

}

Then use it like this:

Date date = format(UTC, "2020-04-19T00:30:07.000Z")

or

String date = parse(UTC, new Date())

You can also define other date formats if you require (not just UTC)

Answer 12

@John-Skeet gave me the clue to fix my own issue around this. As a younger programmer this small issue is easy to miss and hard to diagnose. So Im sharing it in the hopes it will help someone.

My issue was that I wanted to parse the following string contraining a time stamp from a JSON I have no influence over and put it in more useful variables. But I kept getting errors.

So given the following (pay attention to the string parameter inside ofPattern();

String str = "20190927T182730.000Z"

LocalDateTime fin;
fin = LocalDateTime.parse( str, DateTimeFormatter.ofPattern("yyyyMMdd'T'HHmmss.SSSZ") );

Error:

Exception in thread "main" java.time.format.DateTimeParseException: Text 
'20190927T182730.000Z' could not be parsed at index 19

The problem? The Z at the end of the Pattern needs to be wrapped in 'Z' just like the 'T' is. Change "yyyyMMdd'T'HHmmss.SSSZ" to "yyyyMMdd'T'HHmmss.SSS'Z'" and it works.

Removing the Z from the pattern alltogether also led to errors.

Frankly, I'd expect a Java class to have anticipated this.