How can I create an Array of ArrayLists?

Question

I am wanting to create an array of arraylist like below:

ArrayList<Individual>[] group = new ArrayList<Individual>()[4];

But it's not compiling. How can I do this?

Answer 1

As per Oracle Documentation:

"You cannot create arrays of parameterized types"

Instead, you could do:

ArrayList<ArrayList<Individual>> group = new ArrayList<ArrayList<Individual>>(4);

As suggested by Tom Hawting - tackline, it is even better to do:

List<List<Individual>> group = new ArrayList<List<Individual>>(4);

Answer 2

As the others have mentioned it's probably better to use another List to store the ArrayList in but if you have to use an array:

ArrayList<Individual>[] group = (ArrayList<Individual>[]) new ArrayList[4];

You will need to suppress the warning but it's safe in this case.

Answer 3

This works:

ArrayList<String>[] group = new ArrayList[4];

Though it will produce a warning that you may want to suppress.

Answer 4

You can create a class extending ArrayList

class IndividualList extends ArrayList<Individual> {

}

and then create the array

IndividualList[] group = new IndividualList[10];

Answer 5

You can create Array of ArrayList

List<Integer>[] outer = new List[number];
for (int i = 0; i < number; i++) {
    outer[i] = new ArrayList<>();
}

This will be helpful in scenarios like this. You know the size of the outer one. But the size of inner ones varies. Here you can create an array of fixed length which contains size-varying Array lists. Hope this will be helpful for you.

In Java 8 and above you can do it in a much better way.

List<Integer>[] outer = new List[number];
Arrays.setAll(outer, element -> new ArrayList<>());

Answer 6

This works, array of ArrayList. Give it a try to understand how it works.

import java.util.*;

public class ArrayOfArrayList {
    public static void main(String[] args) {

        // Put the length of the array you need
        ArrayList<String>[] group = new ArrayList[15];
        for (int x = 0; x < group.length; x++) {
            group[x] = new ArrayList<>();
        }

        //Add some thing to first array
        group[0].add("Some");
        group[0].add("Code");

        //Add some thing to Secondarray
        group[1].add("In here");

        //Try to output 'em
        System.out.println(group[0]);
        System.out.println(group[1]);
    }
}

Credits to Kelvincer for some of codes.

Answer 7

The problem with this situation is by using a arraylist you get a time complexity of o(n) for adding at a specific position. If you use an array you create a memory location by declaring your array therefore it is constant

Answer 8

You can't create array of generic type. Create List of ArrayLists :

 List<ArrayList<Individual>> group = new ArrayList<ArrayList<Individual>>();

or if you REALLY need array (WARNING: bad design!):

 ArrayList[] group = new ArrayList[4];

Answer 9

1. Creation and initialization

   Object[] yourArray = new Object[ARRAY_LENGTH];
   

2. Write access

   yourArray[i]= someArrayList;
   

   to access elements of internal ArrayList:

   ((ArrayList<YourType>) yourArray[i]).add(elementOfYourType); //or other method
   

3. Read access

   to read array element i as an ArrayList use type casting:

   someElement= (ArrayList<YourType>) yourArray[i];
   

   for array element i: to read ArrayList element at index j

   arrayListElement= ((ArrayList<YourType>) yourArray[i]).get(j);
   

Answer 10

List[] listArr = new ArrayList[4];

Above line gives warning , but it works (i.e it creates Array of ArrayList)

Answer 11

ArrayList<String>[] lists = (ArrayList<String>[])new ArrayList[10]; 

Answer 12

To declare an array of ArrayLists statically for, say, sprite positions as Points:

ArrayList<Point>[] positionList = new ArrayList[2];

public Main(---) {
    positionList[0] = new ArrayList<Point>(); // Important, or you will get a NullPointerException at runtime
    positionList[1] = new ArrayList<Point>();
}

dynamically:

ArrayList<Point>[] positionList;
int numberOfLists;

public Main(---) {
    numberOfLists = 2;
    positionList = new ArrayList[numberOfLists];
    for(int i = 0; i < numberOfLists; i++) {
        positionList[i] = new ArrayList<Point>();
    }
}

Despite the cautions and some complex suggestions here, I have found an array of ArrayLists to be an elegant solution to represent related ArrayLists of the same type.

Answer 13

You can create like this ArrayList<Individual>[] group = (ArrayList<Individual>[])new ArrayList[4];

You have to create array of non generic type and then cast it into generic one.

Answer 14

ArrayList<Integer>[] graph = new ArrayList[numCourses] It works.

Answer 15

I think I'm quite late but I ran into the same problem and had to create an array of arraylists as requested by my project in order to store objects of different subclasses in the same place and here is what I ended up doing:

ArrayList<?>[] items = new ArrayList[4];
ArrayList<Chocolate> choc = new ArrayList<>();
ArrayList<Chips> chips = new ArrayList<>();
ArrayList<Water> water = new ArrayList<>();
ArrayList<SoftDrink> sd = new ArrayList<>();

since each arraylist in the array would contain different objects (Chocolate , Chips , Water and SoftDrink ) --it is a project to simulate a vending machine--. I then assigned each of the Arraylists to an index of the array:

items[0]=choc;
items[1]=chips;
items[2]=water;
items[3]=sd;

Hope that helps if anyone runs into a similar issue.

Answer 16

I find this easier to use...

static ArrayList<Individual> group[];
......
void initializeGroup(int size)
{
 group=new ArrayList[size];
 for(int i=0;i<size;i++)
 {
  group[i]=new ArrayList<Individual>();
 }

Answer 17

You can do thi. Create an Array of type ArrayList

ArrayList<Integer>[] a = new ArrayList[n];

For each element in array make an ArrayList

for(int i = 0; i < n; i++){ 
    a[i] = new ArrayList<Integer>();
}

Answer 18

If you want to avoid Java warnings, and still have an array of ArrayList, you can abstract the ArrayList into a class, like this:

public class Individuals {
    private ArrayList<Individual> individuals;
    
    public Individuals() {
        this.individuals = new ArrayList<>();
    }
    
    public ArrayList<Individual> getIndividuals() {
        return individuals;
    }
}

Then you can safely have:

Individuals[] group = new Individuals[4];

Answer 19

ArrayList<String> al[] = new ArrayList[n+1];
for(int i = 0;i<n;i++){
   al[i] = new ArrayList<String>();
}

Answer 20

you can create a List[] and initialize them by for loop. it compiles without errors:

List<e>[] l;
for(int i = 0; i < l.length; i++){
    l[i] = new ArrayList<e>();
}

it works with arrayList[] l as well.