Determine if a CSS class exists with Javascript

Question

Is there a way to determine whether or not a CSS class exists using JavaScript?

Answer 1

This should be possible to do using the document.styleSheets[].rules[].selectorText and document.styleSheets[].imports[].rules[].selectorText properties. Refer to MDN documentation.

Answer 2

function getAllSelectors() { 
    var ret = [];
    for(var i = 0; i < document.styleSheets.length; i++) {
        var rules = document.styleSheets[i].rules || document.styleSheets[i].cssRules;
        for(var x in rules) {
            if(typeof rules[x].selectorText == 'string') ret.push(rules[x].selectorText);
        }
    }
    return ret;
}


function selectorExists(selector) { 
    var selectors = getAllSelectors();
    for(var i = 0; i < selectors.length; i++) {
        if(selectors[i] == selector) return true;
    }
    return false;
}

Answer 3

Based on the answer, I created a javascript function for searching for a CSS class in the browser's memory -

var searchForCss = function (searchClassName) {
  for (let i = 0; i < document.styleSheets.length; i++) {
    let styleSheet = document.styleSheets[i];
    try {
      for (let j = 0; j < styleSheet.cssRules.length; j++) {
        let rule = styleSheet.cssRules[j];
        // console.log(rule.selectorText)
        if (rule.selectorText && rule.selectorText.includes(searchClassName)) {
          console.log('found - ', rule.selectorText, ' ', i, '-', j);
        }
      }
      if (styleSheet.imports) {
        for (let k = 0; k < styleSheet.imports.length; k++) {
          let imp = styleSheet.imports[k];
          for (let l = 0; l < imp.cssRules.length; l++) {
            let rule = imp.cssRules[l];
            if (
              rule.selectorText &&
              rule.selectorText.includes(searchClassName)
            ) {
              console.log('found - ',rule.selectorText,' ',i,'-',k,'-',l);
            }
          }
        }
      }
    } catch (err) {}
  }
};

searchForCss('my-class-name');

This will print a line for each occurrence of the class name in any of the rules in any of the stylesheets.

Ref - Search for a CSS class in the browser memory

Answer 4

Here is my solution to this. I'm essentially just looping through document.styleSheets[].rules[].selectorText as @helen suggested.

/**
 * This function searches for the existence of a specified CSS selector in a given stylesheet.
 *
 * @param (string) styleSheetName - This is the name of the stylesheet you'd like to search
 * @param (string) selector - This is the name of the selector you'd like to find
 * @return (bool) - Returns true if the selector is found, false if it's not found
 * @example - console.log(selectorInStyleSheet ('myStyleSheet.css', '.myClass'));
 */    

function selectorInStyleSheet(styleSheetName, selector) {
    /*
     * Get the index of 'styleSheetName' from the document.styleSheets object
     */
    for (var i = 0; i < document.styleSheets.length; i++) {
        var thisStyleSheet = document.styleSheets[i].href ? document.styleSheets[i].href.replace(/^.*[\\\/]/, '') : '';
        if (thisStyleSheet == styleSheetName) { var idx = i; break; }
    }
    if (!idx) return false; // We can't find the specified stylesheet

    /*
     * Check the stylesheet for the specified selector
     */
    var styleSheet = document.styleSheets[idx];
    var cssRules = styleSheet.rules ? styleSheet.rules : styleSheet.cssRules;
    for (var i = 0; i < cssRules.length; ++i) {
        if(cssRules[i].selectorText == selector) return true;
    }
    return false;
}

This function offers a speed improvement over other solutions in that we are only searching the stylesheet passed to the function. The other solutions loop through all the stylesheets which is in many cases unnecessary.

Answer 5

1. Document contains Element with class my-class:

   const isExists = !!document.querySelector('.my-class') // boolean
   

2. Existing Element has class my-class:

   const el = document.querySelector(...)
   const isExists = !!el?.classList.contains('my-class') // boolean
   

_{References: querySelector() • classList • contains() • ?. chaining • !! logical not}

Answer 6

/* You can loop through every stylesheet currently loaded and return an array of all the defined rules for any selector text you specify, from tag names to class names or identifiers.

Don't include the '#' or '.' prefix for an id or class name.

Safari used to skip disabled stylesheets, and there may be other gotchas out there, but reading the rules generally works better across browsers than writing new ones. */

function getDefinedCss(s){
    if(!document.styleSheets) return '';
    if(typeof s== 'string') s= RegExp('\\b'+s+'\\b','i'); // IE capitalizes html selectors 

    var A, S, DS= document.styleSheets, n= DS.length, SA= [];
    while(n){
        S= DS[--n];
        A= (S.rules)? S.rules: S.cssRules;
        for(var i= 0, L= A.length; i<L; i++){
            tem= A[i].selectorText? [A[i].selectorText, A[i].style.cssText]: [A[i]+''];
            if(s.test(tem[0])) SA[SA.length]= tem;
        }
    }
    return SA.join('\n\n');
}

getDefinedCss('p')//substitute a classname or id if you like

the latest item in the cascade is listed first.

Answer 7

Building on Helen's answer, I came up with this:

//**************************************************************************
//** hasStyleRule
//**************************************************************************
/** Returns true if there is a style rule defined for a given selector.
 *  @param selector CSS selector (e.g. ".deleteIcon", "h2", "#mid")
 */
  var hasStyleRule = function(selector) {

      var hasRule = function(selector, rules){
          if (!rules) return false;
          for (var i=0; i<rules.length; i++) {
              var rule = rules[i];
              if (rule.selectorText){ 
                  var arr = rule.selectorText.split(',');
                  for (var j=0; j<arr.length; j++){
                      if (arr[j].indexOf(selector) !== -1){
                          var txt = trim(arr[j]);
                          if (txt===selector){
                              return true;
                          }
                          else{
                              var colIdx = txt.indexOf(":");
                              if (colIdx !== -1){
                                  txt = trim(txt.substring(0, colIdx));
                                  if (txt===selector){
                                      return true;
                                  }
                              }
                          }
                      }
                  }
              }
          }
          return false;
      };

      var trim = function(str){
          return str.replace(/^\s*/, "").replace(/\s*$/, "");
      };

      for (var i=0; i<document.styleSheets.length; i++){
          var rules = document.styleSheets[i].rules || document.styleSheets[i].cssRules;
          if (hasRule(selector, rules)){
              return true;
          }

          var imports = document.styleSheets[i].imports;
          if (imports){
              for (var j=0; j<imports.length; j++){
                  rules = imports[j].rules || imports[j].cssRules;
                  if (hasRule(selector, rules)) return true;
              }
          }
      } 

      return false;
  };

Answer 8

You could check and see if an object of the style your are looking for already exists. If it does then the css class must exist because an object is using it. For example if you wanted to make sure that distinctly named svg objects each have their own style:

function getClassName(name) {
    //Are there any elements which use a style named 'name' ?
    if (document.getElementsByClassName(name).length === 0){
        //There are none yest, let's make a new style and add it
        var style = document.createElement('style');
        style.type = 'text/css';
        //Where you might provide your own hash function or rnd color
        style.innerHTML = '.'+name+' { fill: #' + getHashColor(name) + '; background: #F495A3; }';
        //Add the style to the document
        document.getElementsByTagName('head')[0].appendChild(style);
        }
        return name;
    }

Note that this is NOT a good approach if you are looking for a style which isn't necessarily used in your document.

Answer 9

if ($(".class-name").length > 0) {

}

That is a nice way to check the class in HTML by using javascript

Answer 10

Oneliner:

[].slice.call(document.styleSheets)
.reduce( (prev, styleSheet) => [].slice.call(styleSheet.cssRules))
.reduce( (prev, cssRule) => prev + cssRule.cssText)
.includes(".someClass")

Answer 11

function getAllSelectors() {
  var ret = {};
  for(var i=0;i<document.styleSheets.length;i++){
    try {
      var rules = document.styleSheets[i].rules || document.styleSheets[i].cssRules;
      for(var x in rules) {
        if(typeof rules[x].selectorText === 'string'){
          if(ret[rules[x].selectorText] === undefined){
            ret[rules[x].selectorText] = rules[x].style.cssText;
          }
          else {
            ret[rules[x].selectorText] = ret[rules[x].selectorText] + ' ' + rules[x].style.cssText;
          }
        }
      }    
    }
    catch(error){
      console.log(document.styleSheets[i]);
    }
  }
  return ret;
}
function selectorExists(selector) {
  var selectors = getAllSelectors();
  if(selectors[selector] !== undefined){
    return true;
  }
  return false;
}
// var allSelectors = getAllSelectors();