How to find out the starting point for each match in ruby

Question

Say, i have a following string

string = "#Sachin is Indian cricketer. #Tendulkar is right hand batsman. #Sachin has been honoured with the Padma Vibhushan award "

I want o/p as

"#Sachin|0|7;#Tendulkar|29|10;#Sachinn|63|7;"

I tried following

 new_string = ""
 string.scan(/#\S+/).each{|match| new_string+="#{match}|#{string.index(match)}|#{match.length};"  }

which gives me

 "#Sachin|0|7;#Tendulkar|29|10;#Sachin|0|7;" 

So how i will get the starting index of each sub-string?

Answer 1

This is actually quite a non-trivial task, and has been discussed quite a bit in other questions on SO. This is the most common solution:

string = "#Sachin is Indian cricketer. #Tendulkar is right hand batsman. #Sachin has been honoured with the Padma Vibhushan award "
new_string = string.to_enum(:scan,/#\S+/i).inject(''){|s,m| s + "#{m}|#{$`.size}|#{m.length};"}

Answer 2

Based on this thread How do I get the match data for all occurrences of a Ruby regular expression in a string? just quick example:

string = "#Sachin is Indian cricketer. #Tendulkar is right hand batsman. #Sachin has been honoured with the Padma Vibhushan award "
new_string = ""
string
  .to_enum(:scan, /#\S+/)
  .each do |wrd|
    m = Regexp.last_match
    new_string += "#{wrd}|#{m.offset(0)[0]}|#{wrd.length};"
  end
p new_string

Answer 3

Here's one that uses scan:

offset = 0
string.scan(/(#\S*)([^#]*)/).map{|m| v = "#{m[0]}|#{offset}|#{m[0].length};"; offset += m.join.length; v}.join
#=> "#Sachin|0|7;#Tendulkar|29|10;#Sachin|63|7;"