WebView link click open default browser

Question

Right now I have an app that loads a webview and all the clicks are kept within the app. What I would like to do is when a certain link, for example, http://www.google.com is clicked within the app it opens the default browser. If anyone has some ideas please let me know!

score 217 · Answer 1 · edited Feb 22 '18 at 14:32

217

I had to do the same thing today and I have found a very useful answer on StackOverflow that I want to share here in case someone else needs it.

Source (from sven)

webView.setWebViewClient(new WebViewClient(){
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (url != null && (url.startsWith("http://") || url.startsWith("https://"))) {
            view.getContext().startActivity(
                new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
            return true;
        } else {
            return false;
        }
    }
});

edited Feb 22 '18 at 14:32

Linh

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answered Jun 14 '11 at 13:01

Amokrane Chentir

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Note that if the url is relative, (doesn't start with "http://") then it will open inside the app. To avoid this always return true and make relative url links do nothing. – Johan S Jun 04 '13 at 10:48
3

You should check for other protocols in the prefix like rtsp, https and so on. If the links are intended to open a media, it should be redirected to device's media player. If there is no protocol prefix, then identify and provide one. – Abhinav Saxena Feb 20 '14 at 06:10
hey, thanks for this. I have a problem, when I go back from my launched activity, the calling one that had the webview would be finished? How can I make sure the activity containing the webview remain open on back navigation? EDIT: nvm, I had the noHistory set to true, thanks! – Atieh Apr 21 '16 at 23:18
removing it did not help. – Atieh Apr 21 '16 at 23:28
the problem with this is that when i change the URL using loadURL during runtime, the shouldOverrideUrlLoading function/method is triggered. But we dont want this, we only want clicks to open externally, so there need to be a check to see if touched – user2899094 Sep 09 '16 at 23:58
5

Note that `shouldOverrideUrlLoading(WebView view, String url)` is deprecated in API 24. Check [this answer](http://stackoverflow.com/a/38484061/3752244). – Mateus Gondim May 13 '17 at 19:26
From the security perspective it is better to check which url's SHOULD open IN the webview and ALL OTHERS should open in the default browser. – Jonas Erbe Dec 02 '20 at 10:48

score 40 · Answer 2 · edited Jan 02 '21 at 22:11

WebView webview = (WebView) findViewById(R.id.webview);
webview.loadUrl(https://whatoplay.com/);

You don't have to include this code.

// webview.setWebViewClient(new WebViewClient());

Instead use below code.

webview.setWebViewClient(new WebViewClient()
{
  public boolean shouldOverrideUrlLoading(WebView view, String url)
  {
    String url2="https://whatoplay.com/";
     // all links  with in ur site will be open inside the webview 
     //links that start ur domain example(http://www.example.com/)
    if (url != null && url.startsWith(url2)){
      return false;
    } 
     // all links that points outside the site will be open in a normal android browser
    else
    {
      view.getContext().startActivity(
      new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
      return true;
    }
  }
});

score 14 · Answer 3 · edited Mar 09 '15 at 01:00

14

You only need to add the following line

yourWebViewName.setWebViewClient(new WebViewClient());

Check this for official documentation.

edited Mar 09 '15 at 01:00

Ram

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answered Mar 09 '15 at 00:18

b1programmer

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score 11 · Answer 4 · edited Dec 21 '11 at 14:58

11

you can use Intent for this:

Intent browserIntent = new Intent("android.intent.action.VIEW", Uri.parse("your Url"));
startActivity(browserIntent);

edited Dec 21 '11 at 14:58

Amokrane Chentir

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answered Nov 20 '10 at 04:42

Piyush

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you should use Intent.ACTION_VIEW – rajh2504 Aug 03 '11 at 01:01

score 6 · Answer 5 · edited May 10 '12 at 10:57

6

You can use an Intent for this:

Uri uriUrl = Uri.parse("http://www.google.com/"); 
Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uriUrl);  
startActivity(launchBrowser);

edited May 10 '12 at 10:57

Perception

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answered May 10 '12 at 06:44

BasavRaj

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score 3 · Answer 6 · answered Feb 18 '21 at 08:23

As this is one of the top questions about external redirect in WebView, here is a "modern" solution on Kotlin:

webView.webViewClient = object : WebViewClient() {
        override fun shouldOverrideUrlLoading(
            view: WebView?,
            request: WebResourceRequest?
        ): Boolean {
            val url = request?.url ?: return false
            //you can do checks here e.g. url.host equals to target one
            startActivity(Intent(Intent.ACTION_VIEW, url))
            return true
        }
    }

score 0 · Answer 7 · answered Aug 18 '23 at 07:50

Now that public boolean shouldOverrideUrlLoading(WebView view, String url) is deprecated and public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) is used instead, you can use the following code in Java:

private class MyWebViewClient extends WebViewClient {
        public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
            if (Objects.equals(request.getUrl().toString(), "http://www.google.com/")) {
                Uri uri = request.getUrl();
                startActivity(new Intent(Intent.ACTION_VIEW, uri));
                return true;
            }
            else {
                return false;
            }
        }
    }

Just replace http://www.google.com/ with the URL you want to open in web browser instead of webview.

WebView link click open default browser

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