There is not a specific Django ORM way (as far as I know) but you can do the following to get a dictionary of entries grouped by the values of a field:
Use .values_list()
with flat=True
to get a list of the existent values in your database (if you don't know them beforehand). Also, use .distinct()
to eliminate duplicate values as we do not care for those:
value_list = MyModel.objects.values_list(
'interesting_field', flat=True
).distinct()
Iterate through value_list
and fill your dictionary:
group_by_value = {}
for value in value_list:
group_by_value[value] = MyModel.objects.filter(interesting_field=value)
Now, the group_by_value
dictionary contains as keys the distinct values in your interesting_field
and as values the queryset objects, each containing the entries of MyModel
with interesting_field=a value from value_list
.
Leaving this here for comment legacy reasons.
I have made a Q&A style example in, which simulates a COUNT ... GROUP BY
SQL query.
Essentially you need to utilize the .order_by
for grouping and the .annotate()
to count on the model's .values()
.
Here is the above-mentioned example:
We can perform a COUNT ... GROUP BY
SQL equivalent query on Django ORM, with the use of annotate()
, values()
, order_by()
and the
django.db.models
's Count
methods:
Let our model be:
class Books(models.Model):
title = models.CharField()
author = models.CharField()
Let's assume that we want to count how many book objects per distinct author exist in our Book table:
result = Books.objects.values('author')
.order_by('author')
.annotate(count=Count('author'))
Now result contains a queryset with two columns: author and count:
author | count
------------|-------
OneAuthor | 5
OtherAuthor | 2
... | ...