How to pass GridView row to TemplateField function?

Question

I have a GridView that has 3 columns: FirstName, LastName and a TemplateField FullName where I string together FirstName and LastName.

Assuming calling DisplayFullName is the function I want to use to concatenate FirstName and LastName, how do I pass the row argument to the function and how to declare the parameter of the function? Thanks.

Here's my code for the FullName column:

        <asp:TemplateField HeaderText="FullName">
            <ItemTemplate>
                <%# DisplayFullName(???) %>
            </ItemTemplate>
        </asp:TemplateField>

Here's my declaration for the function:

protected string DisplayFullName(???)
  { ... }

The ??? are where I need help. OR do I need to pass the row at all? If each time DisplayFullName is called, the 'current' row is known. If so, how do I access the current row in DisplayFullName?

I simplified the operation for the sake of clarity of the question. In reality, there can be up to 20 values in the row I need and I want to do some calculations in the function called.

score 3 · Answer 1 · answered Aug 04 '16 at 22:35

Had to post since nobody seemed to give you an answer that does exactly what you ask for - passing the row to a backend function.

Simply pass "Container.DataItem" to your function - this is the DataRow

<asp:TemplateField>
    <ItemTemplate> 
        <%# DisplayFullName(Container.DataItem) %>
    </ItemTemplate> 
</asp:TemplateField>

then in the CodeBehind you can manipulate it as a DataRowView:

public string DisplayFullName(object containerDataItem)
{
    string firstName = ((DataRowView)containerDataItem)["FirstName"].ToString();
    string lastName = ((DataRowView)containerDataItem)["LastName"].ToString();
    ...

Hope this helps!

Finally somebody answered the question that was actually asked. Thanks! — Brobic Vripiat, Sep 09 '22 at 19:24

score 1 · Answer 2 · answered Apr 04 '12 at 05:06

1

I don't know why you are calling a function here to display full name. You can use like this in your code to achieve full name:

    <asp:TemplateField HeaderText="Name">
                <ItemTemplate>
                    <%#Eval("FirstName") %>&nbsp;<%#Eval("LastName") %>   
                </ItemTemplate>
            </asp:TemplateField>
</asp:TemplateField>

answered Apr 04 '12 at 05:06

Neha

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I added a clarification in my question. The scenario is more complicated. In reality, I need to do some calculations for the TemplateField. – RJIGO Apr 04 '12 at 05:19
<%# FunctionName(parameter1, parameter2, ..., parameterN) %> call your function like this. the parameter may be your rowid or firstname, last name anything. – Neha Apr 04 '12 at 05:21
This is not what I want to do. Because all the arguments are contained in the row. There can be up to 20 arguments. So all I should pass is the row then extract all the data from the row in the called function. – RJIGO Apr 04 '12 at 05:27
Then simply pass your data key in function & then get your items. Refer this.. might be help you http://forums.asp.net/t/1645113.aspx/1 – Neha Apr 04 '12 at 05:31

R.D. · Accepted Answer · 2012-04-04T06:01:55.293

@RJIGO: You can use function like this:

<asp:TemplateField HeaderText="Name">
     <ItemTemplate>
        <%# DisplayFullName(Eval("FirstName"), Eval("LastName"))%>         
        </ItemTemplate>
     </asp:TemplateField>

and your code behind method will like this

  protected string DisplayFullName(object FirstName, object LastName)
  {
      return Convert.ToString(FirstName)+Convert.ToString(LastName);
  }

How to pass GridView row to TemplateField function?

3 Answers3