What is the easiest way to put an index to a repeater control in .NET?

Question

I want an ASP:NET WebForms Repeater control to put an index next to each of its output rows automatically. How can I do that?

Example:

   Name
1  John
2  Jack
3  Joe

That's so not clear. What have you tried so far? What's your code? — MPelletier, Apr 04 '12 at 10:38

Rawling · Accepted Answer · 2012-04-04T10:49:31.340

32

Try the following:

<asp:Repeater ID="myRepeater" runat="server">
    <HeaderTemplate>
        <table>
    </HeaderTemplate>
    <ItemTemplate>
        <tr>
            <td><%# Container.ItemIndex %></td>
            <!-- or maybe -->
            <td><%# Container.ItemIndex + 1 %></td>
            <td><%# DataBinder.Eval(Container, "DataItem.Name") %></td>
        </tr>
    </ItemTemplate>
    <FooterTemplate>
        </table>
    </FooterTemplate>
</asp:Repeater>

edited Apr 04 '12 at 10:49

answered Apr 04 '12 at 10:42

Rawling

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3

Maybe use a `<%# Container.ItemIndex + 1 %>`, to get a 1-based number. – Hans Keﬆing Apr 04 '12 at 10:46
Cheers, I've put that in. I assume it'll work :) My own use case uses the zero-based index. – Rawling Apr 04 '12 at 10:50
1

I used `DataBinder.Eval(Container, "ItemIndex")` – Marcel Dec 20 '16 at 14:58
how to force repeater generate new itemtemplate on specific index @Rawling – user123456 Sep 29 '20 at 08:55

What is the easiest way to put an index to a repeater control in .NET?

1 Answers1