I need to fill a rectangle with a black to white (transparent) gradient. However, I could only find a GradientBrush
class and all examples I found showed smooth transition and I want sharp bars. That's what I need:
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5
You need to average the colors between your start color and your end color. Here is a routine that does all that, using an averaging formula found here: Generate Color Gradient in C#
private void PaintGradientBars(Graphics g, Rectangle r,
Color startColor, Color endColor, int numBars) {
int rMin = startColor.R;
int gMin = startColor.G;
int bMin = startColor.B;
int rMax = endColor.R;
int gMax = endColor.G;
int bMax = endColor.B;
int left = 0;
for (int i = 0; i < numBars; i++) {
int rAvg = rMin + (int)((rMax - rMin) * i / numBars);
int gAvg = gMin + (int)((gMax - gMin) * i / numBars);
int bAvg = bMin + (int)((bMax - bMin) * i / numBars);
Color useColor = Color.FromArgb(rAvg, gAvg, bAvg);
int width = (r.Width - left) / (numBars - i);
using (SolidBrush br = new SolidBrush(useColor)) {
g.FillRectangle(br, new Rectangle(left, 0, width, r.Height));
}
left += width;
}
}
Then you make a simple call:
private void panel1_Paint(object sender, PaintEventArgs e) {
PaintGradientBars(e.Graphics, panel1.ClientRectangle,
Color.Blue, Color.Green, 5);
}
Resulting in:
2
in this code i use picturebox, play with 'k' and 'i'
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
int k = 20;
Color mycolor = new Color();
for (int i = 0; i < 10; i++)
{
mycolor = Color.FromArgb(i * k, i * k, i * k);
SolidBrush mybrash = new SolidBrush(mycolor);
e.Graphics.FillRectangle((Brush)mybrash, 0 + i * k, 0, k, k);
}
}
Good luck!

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