Popen and python

Question

Working on some code and I'm given the error when running it from the command prompt...

NameError: name 'Popen' is not defined

but I've imported both import os and import sys.

Here's part of the code

exepath = os.path.join(EXE File location is here)
exepath = '"' + os.path.normpath(exepath) + '"'
cmd = [exepath, '-el', str(el), '-n', str(z)]

print 'The python program is running this command:'
print cmd

process = Popen(cmd, stderr=STDOUT, stdout=PIPE)
outputstring = process.communicate()[0]

Am I missing something elementary? I wouldn't doubt it. Thanks!

specify version of Python. some modules were changed in python-2.6 — van, Jun 17 '09 at 15:47
Python 2.5 After saying... process = os.Popen(cmd, stderr=STDOUT, stdout=PIPE) it now gives me the error... NameError: name 'STDOUT' is not defined — Tyler, Jun 17 '09 at 15:53
After that.. WindowsError: [Error 3] The system cannot find the path specified — Tyler, Jun 17 '09 at 18:13
this is not a Python issue. does your exepath exist? you need to ask another question to get proper answers re this error (it has nothing to do with your original question), this question has run its course. — SilentGhost, Jun 17 '09 at 18:56

SilentGhost · Accepted Answer · 2009-06-17T15:54:06.137

38

you should do:

import subprocess
subprocess.Popen(cmd, stderr=subprocess.STDOUT, stdout=subprocess.PIPE)
# etc.

edited Jun 17 '09 at 15:54

answered Jun 17 '09 at 15:43

SilentGhost

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After that.. WindowsError: [Error 3] The system cannot find the path specified – Tyler Jun 17 '09 at 18:11

David Cournapeau · Answer 2 · 2009-06-17T15:50:10.333

7

Popen is defined in the subprocess module

import subprocess
...
subprocess.Popen(...)

Or:

from subprocess import Popen
Popen(...)

edited Jun 17 '09 at 15:50

answered Jun 17 '09 at 15:41

David Cournapeau

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from subprocess import Popen; Popen(...) – van Jun 17 '09 at 15:47
After saying... process = os.Popen(cmd, stderr=STDOUT, stdout=PIPE) it now gives me the error... NameError: name 'STDOUT' is not defined – Tyler Jun 17 '09 at 15:50
process = subprocess.Popen(cmd,stderr=subprocess.STDOUT,stdout=subprocess.PIPE) – Jay Atkinson Jun 17 '09 at 16:32

score 2 · Answer 3 · answered Jun 17 '09 at 15:43

When you import a module, the module's members don't become part of the global namespace: you still have to prefix them with modulename.. So, you have to say

import os
process = os.popen(command, mode, bufsize)

Alternatively, you can use the from module import names syntax to import things into the global namespace:

from os import popen    # Or, from os import * to import everything
process = popen(command, mode, bufsize)

score 1 · Answer 4 · edited Jun 17 '09 at 15:49

If your import looks like this:

import os

Then you need to reference the things included in os like this:

os.popen()

If you dont want to do that, you can change your import to look like this:

from os import *

Which is not recommended because it can lead to namespace ambiguities (things in your code conflicting with things imported elsewhere.) You could also just do:

from os import popen

Which is more explicit and easier to read than from os import *

score 1 · Answer 5 · answered Jun 17 '09 at 15:43

1

This looks like Popen from the subprocess module (python >= 2.4)

from subprocess import Popen

answered Jun 17 '09 at 15:43

Kjetil Joergensen

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score -2 · Answer 6 · answered Jun 17 '09 at 15:40

-2

You should be using os.popen() if you simply import os.

answered Jun 17 '09 at 15:40

Andrew

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I also imported subprocess if that helps clarify anything – Tyler Jun 17 '09 at 15:41
You're invoking "Popen()" when in fact you should be using "os.popen()" – Andrew Jun 17 '09 at 15:43

Popen and python

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