In my website I have a section where I generate HTML from a twitter feed. Here is the php code that wraps the section in HTML:
<p class="columns">
<?
require ("twitter-feed.php");
echo generatetwitter();
?>
</p>
the generatetwitter(); method returns this as a string:
<li class="twitter">“@<a class=" " href="http://twitter.com/lecrae">lecrae</a>: If people throw stones at you, pick em up and build something. <a href="http://search.twitter.com/search?q=%23stayfocused" title="#stayfocused" class=" ">#stayfocused</a>”</li>
When the page generates it shows the code properly in the "View Source" option of Chrome and Firefox, but when I do "inspect element" it shows this
<p class="columns"></p>
<li class="twitter">...</li>
<p></p>
So the class CSS isn't getting applied to the twitter feed. I need the twitter feed to be in the p tags with the class defined.
Some points:
- generatetwitter() returns the HTML in a string
- I've tried having twitter-feed.php (the generatetwitter() method) echoing out the HTML directly, but it makes no difference. I've had the same results every time.
- when the generatetwitter() method is overridden to return only a normal string "eg return "test";" it works normally.
- It seems that this doesn't work if the generatetwitter() method returns anything but regular text (excluding HTML).
or
starting tag for your- element? Also, what doctype are you using?
– Scuzzy Apr 12 '12 at 01:23