Counting to Scalar Value

Question

So I have a foreach loop:

foreach (1..10) {
    print "#", $t, "\n";
 }

But I also have a scalar:

$number = 5;

Can I count from 1 to the scalar like so?

 foreach (1..$number) {
    print "#", $t, "\n";
 }

When I do this, the program simply outputs nothing. What can I do to make this work?

You are using the variable `$t` in the loop body, but do not define it. [`use strict; use warnings;`](http://stackoverflow.com/questions/8023959/why-use-strict-and-warnings) would have alerted you to your mistake. - `foreach my $t (1..$number) {` works as intended. — daxim, Apr 14 '12 at 16:45
@daxim In the full code, I did define $v... sorry about that. — Dynamic, Apr 19 '12 at 00:56

score 2 · Accepted Answer · answered Apr 14 '12 at 15:58

2

Script:

#!/usr/bin/perl

use strict;
use warnings;

my $number = 5;

foreach (1..$number) {
  print "#$_\n";
}

or

#!/usr/bin/perl

use strict;
use warnings;

my $number = 5;

print "#$_\n" for 1..$number;

Output:

#1
#2
#3
#4
#5

answered Apr 14 '12 at 15:58

Ωmega

1 Answers1