Hexa String to Int java

Question

I have:

int number = 0x00000024;

And it have no problems, but now im get it from with de format:

<MAN>
      <NAME hexa="0x00000001"/>
</MAN>

And I try to parse hexa with:

Integer.parseInt(parser.getAttributeValue(0), 16)

But it says:

Unable to parse '0x00000001' as integer

Anyone knows whats happening?

See also this question: http://stackoverflow.com/questions/5153811/how-to-convert-a-hexadecimal-string-to-long-in-java — DRCB, Apr 16 '12 at 14:42
http://stackoverflow.com/questions/923863/converting-a-string-to-hexadecimal-in-java — scibuff, Apr 16 '12 at 14:42

score 6 · Accepted Answer · answered Apr 16 '12 at 14:40

6

Remove the 0x:

Integer.parseInt(parser.getAttributeValue(0).substring(2), 16)

answered Apr 16 '12 at 14:40

MByD

3

Actually, the answer in @DRCB's link is even better Integer.decode: http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#decode(java.lang.String) – MByD Apr 16 '12 at 14:45

score 0 · Answer 2 · edited May 23 '17 at 12:20

0

int num = Long.decode(parser.getAttributeValue(0)).intValue();

edited May 23 '17 at 12:20

Community

answered Apr 16 '12 at 16:20

trutheality

CHeck the first answer, I'll prefer that – Daniel Gomez Rico Apr 18 '12 at 13:41
@Daniel I prefer this method mainly because it decodes other formats correctly. Also it doesn't create an additional intermediate string object. – trutheality Apr 18 '12 at 15:41

2 Answers2