I have a Java program running on a Linux computer, and want to find the process ID (pid) of its process. I know the ps
command can provide this information, but its output is confusing because it has so much extraneous information. How can I get just the pid?
I am using MPJ library in java program for Pagerank algorithm. I compile it by
javac -cp .:$MPJ_HOME/lib/mpj.jar MpiPageRank.java
and run by
mpjrun.sh -np 2 MpiPageRank
where -np
is number of process
Now i have to find its pid
ps -ef|grep java
like
mpjrun.sh -np 2 MpiPageRank & sleep 2
ps -ef | grep java
I get
pnewaska 27866 27837 99 21:28 pts/45 00:00:09 java -cp /u/pnewaska/mpj-v0_38/lib/smpdev.jar:/u/pnewaska/mpj-v0_38/lib/xdev.jar:/u/pnewaska/mpj-v0_38/lib/mpjbuf.jar:/u/pnewaska/mpj-v0_38/lib/loader2.jar:/u/pnewaska/mpj-v0_38/lib/starter.jar:/u/pnewaska/mpj-v0_38/lib/mpiExp.jar runtime.starter.MulticoreStarter /nfs/nfs1/home/pnewaska/DistributedSystems/Project3 10 smpdev useLocalLoader EMPTY MpiPageRank -i input.500k0 -n 10 -o
Now I want to extract MpiPageRank
from only 1 linux comman to get its pid ie 27866
.
how do i do that ?