Why is this long double not printing out correctly using printf?

Question

I need to do division using long double, on the order of 1/10^23, however the numbers get cut off when i check them using printf. Does anyone one know how I can see the full number? For example:

long double a = 1;
long double b = 3;
printf ("%Lf", a/b );

But I get:

0.333333

For example I would like to display the full number like here

@cnicutar at least the 80 bits of long double, this is just an example — mihajlv, Apr 18 '12 at 20:19
`.3333333...` will never show up due to the limited precision of floating-point numbers. However, you could tell `printf` how many digits to display. — cHao, Apr 18 '12 at 20:21
http://stackoverflow.com/questions/4089174/printf-and-long-double — Larry Battle, Apr 18 '12 at 20:21
Whether you'll ever get to print the precision you expect is implementation dependent. For example, in MSVC `long double` is the same as `double` — Praetorian, Apr 18 '12 at 20:22

score 3 · Accepted Answer · edited Apr 18 '12 at 20:22

3

%f format prints with 6 digits after the decimal point. You can use %.df to print d digits. Or better yet, use %.dg to make large/small values readable as well.

edited Apr 18 '12 at 20:22

cHao

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answered Apr 18 '12 at 20:19

janneb

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Why is this long double not printing out correctly using printf?

1 Answers1