How to print 64-bit integer in GCC 4.4.1?

Question

I am using Code::Blocks with GCC 4.4.1 and I seem to be unable to print 64-bit signed integers from my C-code.

This code:

long long longint;

longint = 0x1BCDEFABCDEFCDEF; /* 2003520930423229935 */
printf("Sizeof: %d-bit\n", sizeof(longint) * 8);     /* Correct */
printf("%llx\n", longint);                           /* Incorrect */
printf("%x%x\n", *(((int*)(&longint))+1), longint);  /* Correct */
printf("%lld\n", longint);                           /* Incorrect */

Produces output:

Sizeof: 64-bit
cdefcdef
1bcdefabcdefcdef
-839922193

64-bit arithmetic seems to work correctly:

longint -= 0x1000000000000000;
printf("%x%x\n", *(((int*)(&longint))+1), longint);

Gives:

bcdefabcdefcdef

Am I missing something?

Possible duplicate of [this question](http://stackoverflow.com/questions/2844/how-do-you-printf-an-unsigned-long-long-int). — npclaudiu, Apr 19 '12 at 06:49
How is the second printf incorrect? Ah, I see in the example now. Never mind. The example prints out the right value for me on Linux. — , Apr 19 '12 at 06:50
`%lld` and `%llx` are correct format directives for printing a value of type `long long` (in C99). If it doesn't work, there's something broken in the installation, e.g., mismatched or broken libraries. — torek, Apr 19 '12 at 06:56
For anyone still thinking of using GCC 4.4.1 - that compiler is now over a decade old, and was 2.5 years old at the time the question was asked :) — Kuba hasn't forgotten Monica, Mar 12 '20 at 14:13
@ReinstateMonica I worked in aerospace back then. It is not uncommon to work with 20 years old software and compilers. — Fenikso, Mar 25 '20 at 13:50
@Fenikso That's perfectly fine then - I'd rather it be this way, in fact :) — Kuba hasn't forgotten Monica, Mar 27 '20 at 15:21

score 11 · Accepted Answer · answered Apr 19 '12 at 06:54

11

See if %I64d helps you. %lld is fine for long long int but things get really different sometimes on Windows IDEs

answered Apr 19 '12 at 06:54

Pavan Manjunath

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score 11 · Answer 2 · edited May 23 '17 at 10:31

11

To (in C99 and up) portably print 64 bit integers, you should #include <inttypes.h> and use the C99 macros PRIx64 and PRId64. That would make your code;

printf("Sizeof: %d-bit\n", sizeof(longint) * 8);
printf("%" PRIx64 "\n", longint);
printf("%" PRId64 "\n", longint);

Edit: See this question for more examples.

edited May 23 '17 at 10:31

Community

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answered Apr 19 '12 at 06:56

Joachim Isaksson

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2

Those are technically formats for `int64_t`, in case that happens to differ from `long long`. Of course there's some chance that they actually *work* on existing broken/not-quite-C99-still-yet systems. :-) – torek Apr 19 '12 at 06:58

score 6 · Answer 3 · answered Apr 19 '12 at 06:59

This is OS dependent. If you're doing this on just about any GCC that uses GLIBC, then %llx works.

However if you are using mingw compiler, then this uses Microsoft libraries, and you need to look into their documentation.

This changes your program to:

longint = 0x1BCDEFABCDEFCDEFLL; /* 2003520930423229935 */
printf("Sizeof: %d-bit\n", sizeof(longint) * 8);     /* Correct */
printf("%I64x\n", longint);                           /* Incorrect */
printf("%x%x\n", *(((int*)(&longint))+1), longint);  /* Correct */
printf("%I64d\n", longint);

score 1 · Answer 4 · answered Mar 12 '20 at 13:49

1

longint = 0x1BCDEFABCDEFCDEF; /* 2003520930423229935 */ you can print as-

printf("%llx", longint);

answered Mar 12 '20 at 13:49

Amit Rai

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score 0 · Answer 5 · answered Apr 19 '12 at 06:57

0

Finally got it:

longint = 0x1BCDEFABCDEFCDEF; /* 2003520930423229935 */
printf("%I64d\n", longint);
printf("%I64x\n", longint);

Prints:

2003520930423229935
1bcdefabcdefcdef

Thanks @npclaudiu!

answered Apr 19 '12 at 06:57

Fenikso

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How to print 64-bit integer in GCC 4.4.1?

5 Answers5