POST request succeeds in cURL but fails in Java

Question

The following is a snippet for uploading files using PHP. I am an Android developer and I want to upload a file. Which means I have to send a POST request to a URL that contains this script.

What is the parameter name that I should use if I want to upload a file?

PHP

if (file_exists("upload/" . $_FILES["file"]["name"])) {
    echo $_FILES["file"]["name"] . " already exists. ";
} else {
    move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]);
    echo "https://some.site/upload/" . $_FILES["file"]["name"];
}

When I try cURL, the file is uploaded successfully but when I do it via Java, it fails.

cURL

curl -F file=@call_me_now_2.wav http://some.site/upload/

Java Code

    File f = new File("call_me_now_11.wav");

    HttpPost filePost = new HttpPost("https://some.site/upload/");
    FileEntity fileEntity = new FileEntity(f, "audio/wav");
    filePost.setEntity(fileEntity);

    HttpClient client = new DefaultHttpClient();
    client.execute(filePost, new BasicResponseHandler() {

        @Override
        public String handleResponse(HttpResponse response)
                throws HttpResponseException, IOException {
            HttpEntity entity = response.getEntity();
            InputStream content = entity.getContent();

            int c = 0;
            StringBuilder builder = new StringBuilder();
            while((c = content.read()) != -1) {
                builder.append((char) c);
            }
            System.out.println(builder.toString());

            return builder.toString();
        }
    });

score 1 · Accepted Answer · edited May 23 '17 at 12:03

1

Answered by this. But nevertheless an explanation.

One cannot read a binary file as done (as text). That gives problems with line endings, nul characters, character encodings, and again making it binary.

One normally would get the InputStream, here content, and stream it out, without first reading all into memory.

import org.apache.commons.fileupload.util.Streams;

OutputStream out = response.getOutputStream();
Streams.copy(content, out, false);

Of course on posting a form with file upload, follow the mentioned answer.

edited May 23 '17 at 12:03

Community

1
1

answered Apr 19 '12 at 09:30

Joop Eggen

107,315
7
83
138

What you have suggested is a different way to handle the response. Can you show me how to deal with the request? – Ragunath Jawahar Apr 23 '12 at 05:32
Sorry rereading my answer I think it inadequate. The form input name should be `file`. – Joop Eggen Apr 23 '12 at 09:36
Worked out, that was exactly the one I was looking for. Thanks. – Ragunath Jawahar Apr 23 '12 at 14:48

POST request succeeds in cURL but fails in Java

1 Answers1