How to print jquery object/array

Question

I get id and category name from mysql database.

When I am alerting a result, I get:

[{"id":"197","category":"Damskie"},"id":"198","category":"M\u0119skie"}]

(Is this object?)

How can I print a result like this:

Damskie

M\u0119skie
M\u0119ski - has bad encoding. It should be Męskie. How can I change this?

score 33 · Accepted Answer · answered Apr 19 '12 at 15:51

33

var arrofobject = [{"id":"197","category":"Damskie"},{"id":"198","category":"M\u0119skie"}];

$.each(arrofobject, function(index, val) {
    console.log(val.category);
});

answered Apr 19 '12 at 15:51

thecodeparadox

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score 8 · Answer 2 · edited Nov 23 '16 at 13:26

8

What you have from the server is a string like below:

var data = '[{"id":"197","category":"Damskie"},{"id":"198","category":"M\u0119skie"}]';

Then you can use JSON.parse function to change it to an object. Then you access the category like below:

var dataObj = JSON.parse(data);

console.log(dataObj[0].category); //will return Damskie
console.log(dataObj[1].category); //will return Męskie

edited Nov 23 '16 at 13:26

Sonny Chivas

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10

answered Apr 19 '12 at 15:53

Selvakumar Arumugam

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I use this example with jQuery.ajax() and it's working too. Thanks. – Sadu Apr 19 '12 at 16:05

score 4 · Answer 3 · answered Apr 19 '12 at 15:52

4

Your result is currently in string format, you need to parse it as json.

var obj = $.parseJSON(result);
alert(obj[0].category);

Additionally, if you set the dataType of the ajax call you are making to json, you can skip the $.parseJSON() step.

answered Apr 19 '12 at 15:52

Kevin B

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OP never said it is an AJAX call :P – Selvakumar Arumugam Apr 19 '12 at 15:55
@Vega Very true, though if it isn't an ajax call, maybe it doesn't need to be json! – Kevin B Apr 19 '12 at 15:55
haha true.. was just kidding tho. Most likely, It should be an return from AJAX. – Selvakumar Arumugam Apr 19 '12 at 15:56

score 0 · Answer 4 · answered Apr 11 '18 at 06:32

0

var arrofobject = [{"id":"197","category":"Damskie"},{"id":"198","category":"M\u0119skie"}];
var data = arrofobject.map(arrofobject => arrofobject);
console.log(data)

for more details please look at jQuery.map()

answered Apr 11 '18 at 06:32

Parth Raval

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score 0 · Answer 5 · answered Dec 05 '20 at 00:13

0

I was having similar problem and

var dataObj = JSON.parse(data);

console.log(dataObj[0].category); //will return Damskie
console.log(dataObj[1].category); //will return Męskie

This solved my problem. Thanks Selvakumar Arumugam

answered Dec 05 '20 at 00:13

Tanvir Rajeev

13
1
6

How to print jquery object/array

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