How can a peer find another peer?

Question

There is an important issue that is not clear when someone search information about how the peers find each other in JXTA. Let´s assume that we have got two peers one in Berlin and the another one in London, which is a rendezvous. My question is how can the peer in Berlin find the peer in London?

What methods in JXTA to solve this ?
Can you post an example?

If there are only those two peers, and they have no knowledge about each other, they will just not find each other. — Niklas B., Apr 21 '12 at 17:35
Thanks for your replay. Is there any way that I can make them to know each other? — Alex, Apr 21 '12 at 18:03

score 1 · Answer 1 · answered May 24 '12 at 11:10

1

Googling jxta Peer Discovery Protocol we find http://java.sun.com/developer/Books/networking/Wilson/wilson_ch04.pdf.

answered May 24 '12 at 11:10

Zecas

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score 1 · Answer 2 · edited May 23 '17 at 12:22

You need to know the URI of a public Rendezvous peer which is a pre-existing Peer visible to both your peer in London and Berlin. When you start your peers, you seed the NetworkConfigurator with this rendezvous peer's URI, something like this:

NetworkManager manager = new NetworkManager(...)
NetworkConfigurator config = manager.getConfigurator();
config.addRdvSeedingURI("tcp://123.123.123.123:1234");

I think @JVerstry says something similar here: https://stackoverflow.com/a/4953034/1240660

How can a peer find another peer?

2 Answers2