how to call base class method from derive class in c++?

Question

Possible Duplicate:
Is there a way to call an object's base class method that's overriden? (C++)

First question is calling super() constructor in java same as initializing the super class constructor first in c++ like.

sub() : super(){}

is there a way to call super class method in c++ like in java

ex.

public sub(){
super.someMethod(); 

}

Answer 1

To call the base constructor of a class, you call it as BaseClassName(args). For example:

class A
{
public:
    A() { }
    virtual void Foo() { std::cout << "A's foo" << std::endl; }
};

class B : public A
{
public:
    B() : A() { }
    void Foo();
};

To call the base class version of a method, you do BaseClassName::MethodName:

void B::Foo()
{
    std::cout << "B's foo" << std::endl;
    A::Foo();
}