how to read fields extension starting from index 'n' in csv file based on their extension in java

Question

I had a requirement like, i want to test the file extension of the fields starting from index 10 in the following code:

Sunset.jpg;REF;Title;DESC;10;1;11;21;31;Bluehills.jpg;Winter.ppt;Moonfit.xls...

In the above code i want to read the extesnsion of the fields starting from inedx 10(Bluehills.jpg and soon), to check whether it is valid extension or not.

Any help is highly appreciated.

Thanks,

Raj

What have you tried? Do you know how to get array or list elements by index, and how to use regular expressions? — Thilo, Apr 22 '12 at 02:05
Hi @Thilo i have tried using CSV Reader..i got to read the fields but how to get the fieds extension particularly startig from an index as i mentioned above — user27, Apr 22 '12 at 02:10
possible duplicate of [Java: splitting the filename into a base and extension](http://stackoverflow.com/questions/4545937/java-splitting-the-filename-into-a-base-and-extension) — Thilo, Apr 22 '12 at 02:11

score 0 · Accepted Answer · answered Apr 22 '12 at 02:15

Read the file and parse the line(s) as String
Make a substring from index n to string.length().
Split the the file names in a String ArrayList using the split() function with ";" as delimiter.

Use the following function to retrieve the file extension

public static String getExtension(File f) {
    String ext = null;
    String s = f.getName();
    int i = s.lastIndexOf('.');

    if (i > 0 &&  i < s.length() - 1) {
        ext = s.substring(i+1).toLowerCase();
    }
    return ext;
 }

how to read fields extension starting from index 'n' in csv file based on their extension in java

1 Answers1