How to generate xml in Java?

Question

Please, tell me, how to generate XML in Java? I couldn't find any example using SAX framework.

What do you need? Read an xml file from java or generate an xml file from java? — dash1e, Apr 22 '12 at 10:13
possible duplicate of [Generating XML using SAX and Java](http://stackoverflow.com/questions/4898590/generating-xml-using-sax-and-java) — svick, Apr 22 '12 at 14:56

yegor256 · Answer 1 · 2014-09-09T17:19:23.200

2

Try Xembly, a small open source library that wraps native Java DOM with a "fluent" interface:

String xml = new Xembler(
  new Directives()
    .add("root")
    .add("order")
    .attr("id", "553")
    .set("$140.00")
).xml();

Will generate:

<root>
  <order id="553">$140.00</order>
</root>

edited Sep 09 '14 at 17:19

answered Oct 13 '13 at 13:37

yegor256

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Thank you for reply. Although this is not a built-in library, interesting advice. – Jake Badlands Oct 24 '13 at 11:13

score 1 · Answer 2 · answered Apr 22 '12 at 10:14

1

SAX is a library to parse existing XML files with Java. It is not to create a new XML file out of Java. If you want to do this use a library like DOM4J to create a XML tree and then write it to a file.

answered Apr 22 '12 at 10:14

Thomas Uhrig

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score 1 · Accepted Answer · edited May 23 '17 at 11:46

1

See this, this, Generating XML using SAX and Java and this

edited May 23 '17 at 11:46

Community

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answered Apr 22 '12 at 10:14

Tejas Patil

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Ahamed Mustafa M · Answer 4 · 2012-04-22T14:19:15.583

You can also use libraries like JAXB or SimpleXML or XStream if you want to easily map/convert your java objects to XML.

Say we have a simple entity/pojo - Item.The properties of the pojo class can be made the XML's element or attribute with simple annotations.

@Entity @Root public class Item {

@Attribute
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private Long id;

@Transient
@ManyToOne
private Order order;

@Element
private String product;

@Element
private double price;

@Element
private int quantity; }

To generate XML from this item, the code can be simply

Serializer serializer=new Persister();//SimpleXML serializer
    Item itemToSerializeToXml=new Item(2456L, "Head First Java", 250.00,10);//Object to be serialized
    StringWriter destinationXMLWriter=new StringWriter();//Destination of XML
    serializer.write(itemToSerializeToXml,destinationXMLWriter);//Call to serialize the POJO to XML
    System.out.println(destinationXMLWriter.toString());

Above code generated XML: ` Head First Java 250.0 10 ` – Ahamed Mustafa M Apr 22 '12 at 14:20 — Ahamed Mustafa M, Apr 22 '12 at 14:20
Doesn't compile, since none of the annotations is defined. – David Conrad Mar 01 '13 at 19:42 — David Conrad, Mar 01 '13 at 19:42

score 1 · Answer 5 · answered Apr 22 '12 at 10:24

1

use dom4j, here is quick start for dom4j

dom4j guide

answered Apr 22 '12 at 10:24

Nurlan

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score 1 · Answer 6 · answered May 19 '16 at 16:10

I found a nice library for XML creation on GitHub at https://github.com/jmurty/java-xmlbuilder . Really good for simple documents at least (I didn't have an opportunity to employ it for anything bigger than around a dozen lines).

The good thing about this library is that each of its commands (i.e. create attribute, create element, etc.) has 3 levels of abbreviations. For example, to add the tag <foo> to the document you can use the following methods:

.e("foo") (single-letter form)
.elem("foo" (4 letter form)
.element("foo") (fully spelled-out form)

This allows creating XML using both longer and more abbreviated code, as appropriate, so it can be a good fit for a variety of coding styles.

How to generate xml in Java?

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