I need to return year and week of a given date. Sounds simple. But to be right 2012-01-01 have to return 2011-52, because week 1 in 2012 starts January 2th.
To find the week, I use:
GregorianCalendar calw = new GregorianCalendar(GregorianCalendarTypes.Localized);
return calw.GetWeekOfYear(DateTime.Parse("2012-01-01"), CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday).ToString();
this return 52. (correct)
But how do I get the Year?
edit:
With the help from here: http://codebetter.com/petervanooijen/2005/09/26/iso-weeknumbers-of-a-date-a-c-implementation/
This seems to work:
private int weekYear(DateTime fromDate)
{
GregorianCalendar cal = new GregorianCalendar(GregorianCalendarTypes.Localized);
int week = weekNumber(fromDate);
int month = cal.GetMonth(fromDate);
int year = cal.GetYear(fromDate);
//week starts after 31st december
if (week > 50 && month == 1)
year = year - 1;
//week starts before 1st January
if (week < 5 && month == 12)
year = year + 1;
return year;
}
private int weekNumber(DateTime fromDate)
{
// Get jan 1st of the year
DateTime startOfYear = fromDate.AddDays(-fromDate.Day + 1).AddMonths(-fromDate.Month + 1);
// Get dec 31st of the year
DateTime endOfYear = startOfYear.AddYears(1).AddDays(-1);
// ISO 8601 weeks start with Monday
// The first week of a year includes the first Thursday
// DayOfWeek returns 0 for sunday up to 6 for saterday
int[] iso8601Correction = { 6, 7, 8, 9, 10, 4, 5 };
int nds = fromDate.Subtract(startOfYear).Days + iso8601Correction[(int)startOfYear.DayOfWeek];
int wk = nds / 7;
switch (wk)
{
case 0:
// Return weeknumber of dec 31st of the previous year
return weekNumber(startOfYear.AddDays(-1));
case 53:
// If dec 31st falls before thursday it is week 01 of next year
if (endOfYear.DayOfWeek < DayOfWeek.Thursday)
return 1;
else
return wk;
default: return wk;
}
}