Removing a part of a URL with Ruby

Question

Removing the query string from a URL in Ruby could be done like this:

url.split('?')[0]

Where url is the complete URL including the query string (e.g. url = http://www.domain.extension/folder?schnoo=schnok&foo=bar).

Is there a faster way to do this, i.e. without using split, but rather using Rails?

edit: The goal is to redirect from http://www.domain.extension/folder?schnoo=schnok&foo=bar to http://www.domain.extension/folder.

EDIT: I used:

url = 'http://www.domain.extension/folder?schnoo=schnok&foo=bar'
parsed_url = URI.parse(url)
new_url = parsed_url.scheme+"://"+parsed_url.host+parsed_url.path

I am not sure if I completely understand your goal. Do you want extract parameters from request in your controller? — Suborx, May 02 '12 at 09:12
Is this the URL from the current request, or just a completely arbitrary URL? — Andrew Marshall, May 02 '12 at 09:14
You need to add port if present (and other than 80): `new_url = "#{parsed_url.scheme}://#{parsed_url.host}#{parsed_url.port != 80 ? (':'+parsed_url.port) : ''}#{parsed_url.path}"` — hammady, Jun 15 '15 at 05:41
@hammady - `+parsed_url.port` won't work without explicit converting to string first. Use `+parsed_url.port.to_s` instead. — silverdr, Dec 13 '16 at 10:19
@silverdr that's right, didn't test it, should be `(':'+parsed_url.port.to_s)` — hammady, Dec 13 '16 at 13:36
The OP asks "is there a _faster_ way to do this" -- I think maybe the answer is "no" — user1070300, Aug 30 '23 at 10:41

score 17 · Answer 1 · answered Jun 24 '15 at 07:19

Easier to read and harder to screw up if you parse and set fragment & query to nil instead of rebuilding the URL.

parsed = URI::parse("http://www.domain.extension/folder?schnoo=schnok&foo=bar#frag")
parsed.fragment = parsed.query = nil
parsed.to_s

# => "http://www.domain.extension/folder"

score 7 · Accepted Answer · edited May 23 '17 at 11:45

7

 url = 'http://www.domain.extension/folder?schnoo=schnok&foo=bar'
 u = URI.parse(url)
 p = CGI.parse(u.query)
 # p is now {"schnoo"=>["schnok"], "foo"=>["bar"]}

Take a look on the : how to get query string from passed url in ruby on rails

edited May 23 '17 at 11:45

Community

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answered May 02 '12 at 09:17

swati

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score 6 · Answer 3 · edited Dec 01 '13 at 21:04

6

You can gain performance using Regex

'http://www.domain.extension/folder?schnoo=schnok&foo=bar'[/[^\?]+/]

#=> "http://www.domain.extension/folder"

edited Dec 01 '13 at 21:04

Boris Brodski

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answered Aug 14 '13 at 16:20

zetanova

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zhongxiao37 · Answer 4 · 2012-05-02T09:20:01.160

0

Probably no need to split the url. When you visit this link, you are pass two parameters to back-end:

http://www.domain.extension/folder?schnoo=schnok&foo=bar params[:schnoo]=schnok params[:foo]=bar

Try to monitor your log and you will see them, then you can use them in controller directly.

edited May 02 '12 at 09:20

answered May 02 '12 at 09:11

zhongxiao37

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Removing a part of a URL with Ruby

4 Answers4