Shuffling random integers, printing all possibilities

Question

Possible Duplicate:
How to generate all permutations of a list in Python

Say I have a range, 0-2. I want to shuffle these numbers and print out all of the possibilities:

[0, 1, 2]
[0, 2, 1]
[1, 2, 0]
[1, 0, 2]
[2, 0, 1]
[2, 1, 0]

How would I do this in Python for any range 0-N?

See [How to generate all permutations of a list in Python](http://stackoverflow.com/questions/104420/how-to-generate-all-permutations-of-a-list-in-python) and the `range` function. — hobbs, May 03 '12 at 04:51

score 1 · Answer 1 · answered May 03 '12 at 04:51

1

answered May 03 '12 at 04:51

1

No, never `random.shuffle()`. It's not nearly deterministic enough. – Ignacio Vazquez-Abrams May 03 '12 at 04:58
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I meant, `random.shuffle(list(itertools.permutations(*args)))` I assumed that's what OP meant by "I want to shuffle these numbers and print out all possibilities". – Joel Cornett May 03 '12 at 05:30

1 Answers1