Vibrator on Android

Question

I read a lot about this problem on Stackoverflow but not of the Helps her works at my problem.

In my Source Code I have this.

vibretor  = (Vibrator) this.getSystemService(VIBRATOR_SERVICE);
vibretor.vibrate(600);

and in the AndroidManifeste.xml I have the Permission

<uses-permission android:name="android.permission.VIBRATE"/>

this is all right I think because i looked it up at http://developer.android.com

but it does not worke at all :( So have someone of you a idea how I can get it working?

My testing Devices are: Eee Pad Transformer, Samsung Galaxy S2 and Samsung Galaxy Tab 10.1

See also http://stackoverflow.com/q/3108154/517561, http://stackoverflow.com/q/4430781/517561 — Sparky, May 04 '12 at 06:24
did u try some bigger values like 5000 instead of 600, bcoz 600 might be milliseconds which might be minor. — Andro Selva, May 04 '12 at 06:25
Try this `Vibrator vib = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE); vib.vibrate(600);` — COD3BOY, May 04 '12 at 06:29
@AndroSelva Value is not a problem because I have used the same code with a value of 50 and still its felt. — Antrromet, May 04 '12 at 06:32
I tryed it with bigger values like 1000 but it does not work. — Phil, May 04 '12 at 06:41

score 5 · Accepted Answer · edited Jan 07 '15 at 08:37

5

Problem solved.

The problem was that, under android 4.0, the vibration settings must be

Vibration on touch

and not

Ringtone or Notification

and then it work with my code.

vibretor  = (Vibrator) this.getSystemService(VIBRATOR_SERVICE);
vibretor.vibrate(600);

edited Jan 07 '15 at 08:37

Pang

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answered May 07 '12 at 05:48

Phil

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thanks! On my Note3, it is Device>Sound>Vibration Intensity>Notification – OlivierM Jul 29 '14 at 14:55

score 1 · Answer 2 · edited Aug 01 '14 at 09:29

1

public void vibrate(int duration)
              {
   Vibrator v = (Vibrator)getSystemService(Context.VIBRATOR_SERVICE);
   v.vibrate(duration);    
              }
vibrate(10000);

edited Aug 01 '14 at 09:29

Iman Marashi

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answered May 04 '12 at 06:29

Ponmalar

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Why you want to get the parameter as `String` and then convert it to `int`? Why don't you get it as a `int` on first hand? – COD3BOY May 04 '12 at 06:36
I have used this in my Application. In that i have get the vibration duration from textbox, so that i have passed as string. Now check the edited code. – Ponmalar May 04 '12 at 06:43

Vibrator on Android

2 Answers2