Populate asp.net dropdownlist with number

Question

A simple query , i want to populate the dropdownlist with number starting from 17 to 90 , and the last number should be a string like 90+ instead of 90. I guess the logic will be using a for loop something like:

for (int a = 17; a <= 90; a++)
        {
            ddlAge.Items.Add(a.ToString());
        }

Also I want to populate the text and value of each list item with the same numbers. Any ideas?

score 7 · Accepted Answer · answered May 04 '12 at 14:27

7

for (int i = 17; i < 90; i++)
{
    ddlAge.Items.Add(new ListItem(i.ToString(), i.ToString()));
}
ddlAge.Items.Add(new ListItem("90+", "90"));

answered May 04 '12 at 14:27

Tim Schmelter

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score 5 · Answer 2 · edited May 04 '12 at 14:27

5

Try this:

for (int a = 17; a <= 90; a++)
{
    var i = (a == 90 ? a.ToString() + '+': a.ToString());
    ddlAge.Items.Add(new ListItem(i, i));
}

edited May 04 '12 at 14:27

James Johnson

45,496
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answered May 04 '12 at 14:25

rs.

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90

I don't want to be pedantic all the more on a competitive answer, but if i know that the only exception is the last item, why should i put the logic in the for loop at all? Simply add the exceptional item outside of the loop. That makes it also clearer. – Tim Schmelter May 04 '12 at 14:34
i agree with @TimSchmelter , y check all the numbers . – Mr A May 04 '12 at 14:35
@TimSchmelter you are correct, you answered it, so I'll leave mine AS IS. – rs. May 04 '12 at 14:36

score 3 · Answer 3 · answered May 04 '12 at 14:26

3

This is easy enough. You need to instantiate the ListItem class and populate its properties and then add it to your DropDownList.

    private void GenerateNumbers()
    {
        // This would create 1 - 10
        for (int i = 1; i < 11; i++)
        {
            ListItem li = new ListItem();
            li.Text = i.ToString();
            li.Value = i.ToString();
            ddlAge.Items.Add(li);
        }
    }

answered May 04 '12 at 14:26

David East

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1

This only answers part of the question. OP wants the last item to show as `90+` instead of just `90` – James Johnson May 04 '12 at 14:29

score 2 · Answer 4 · answered May 04 '12 at 14:24

2

for (int a = 17; a <= 90; a++)
{
    ddlAge.Items.Add(new ListItem(a.ToString(), a.ToString()));
}

answered May 04 '12 at 14:24

Skorpioh

1,355
1
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30

why you passing the number 2 times – Mr A May 04 '12 at 14:25
It's setting the text and value. – James Johnson May 04 '12 at 14:27
You've forgotten to add `90+` as last item ;) – Tim Schmelter May 04 '12 at 14:32

score 2 · Answer 5 · answered Dec 12 '13 at 13:14

2

for (int i = 17; i <= 90; i++)
{
    ddlAge.Items.Add(new ListItem(i.ToString(), i.ToString()));
}
ddlAge.Items.Insert(0, new ListItem("Select Age", "0")); //First Item
ddlAge.Items.Insert(ddlAge.Items.Count, new ListItem("90+", "90+")); //Last Item

answered Dec 12 '13 at 13:14

Enes Taha Selek

31
5

score 0 · Answer 6 · answered Jul 01 '13 at 16:48

for (int i = 0; i <=91; i++)
    {
        if (i == 0)
        {
            ddlAge.Items.Add("Select Age");
        }
        else if(i<=90)
        {
            ddlAge.Items.Add(i.ToString());
            i++;
        }
        else
        {
         ddlAge.Items.Add("90+");
        }
    }

Populate asp.net dropdownlist with number

6 Answers6

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