I'm trying to use the solution provided here
Instead of getting a dictionary, how can I get a string with the same output i.e. character followed by the number of occurrences
Example:d2m2e2s3
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3How do you want the string to be formatted? – Amber May 06 '12 at 18:10
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Can you explain the input and output? Are you trying to make string from the dictionary `Out[25]: {'d': 2, 'f': 2, 'g': 2, 'q': 5, 'w': 3} ` – cola May 06 '12 at 18:14
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I want the output as d2f2g2q5w3 – TechacK May 06 '12 at 18:21
5 Answers
47
To convert from the dict to the string in the format you want:
''.join('{}{}'.format(key, val) for key, val in adict.items())
if you want them alphabetically ordered by key:
''.join('{}{}'.format(key, val) for key, val in sorted(adict.items()))
gnr
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I want the letters followed by each time it has occurred in the original string in order. – TechacK May 06 '12 at 18:33
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I tried python 2.6, ValueError: zero length field name in format. should be ''.join('{0}{1}'.format(key, val) for key, val in adict.items()) – Sola Yang Aug 06 '15 at 21:47
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3
Is this what you are looking for?
#!/usr/bin/python
dt={'d': 2, 'f': 2, 'g': 2, 'q': 5, 'w': 3}
st=""
for key,val in dt.iteritems():
st = st + key + str(val)
print st
output: q5w3d2g2f2
Or this?
#!/usr/bin/python
dt={'d': 2, 'f': 2, 'g': 2, 'q': 5, 'w': 3}
dt=sorted(dt.iteritems())
st=""
for key,val in dt:
st = st + key + str(val)
print st
output: d2f2g2q5w3
Example with join:
#!/usr/bin/python
adict=dt={'d': 2, 'f': 2, 'g': 2, 'q': 5, 'w': 3}
' '.join('{0}{1}'.format(key, val) for key, val in sorted(adict.items()))
output: 'd2 f2 g2 q5 w3'
cola
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It's not the best variant because list comprehension and string concatenation with `join` is faster – San4ez May 06 '12 at 18:34
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I want the letters followed by each time it has occurred in the original string in order – TechacK May 06 '12 at 18:45
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1
Once you have the dict solution, just use join to join them into a string:
''.join([k+str(v) for k,v in result.iteritems()])
You can replace the '' with whatever separater (including none) you want between numbers
happydave
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I want the letters followed by each time it has occurred in the original string in order – TechacK May 06 '12 at 18:45
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>>> result = {'d': 2, 'f': 2, 'g': 2, 'q': 5, 'w': 3}
>>> ''.join('%s%d' % (k,v) for k,v in result.iteritems())
'q5w3d2g2f2'
or if you want them alphabetically...
>>> ''.join('%s%d' % (k,v) for k,v in sorted(result.iteritems()))
'd2f2g2q5w3'
or if you want them in increasing order of count...
>>> ''.join('%s%d' % (k,v) for k,v in sorted(result.iteritems(),key=lambda x:x[1]))
'd2g2f2w3q5'
Amber
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I want the letters followed by each time it has occurred in the original string in order – TechacK May 06 '12 at 18:38
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Another approach, avoiding the % interpolation (or format()) by using join() only:
''.join(''.join((k, str(v))) for k,v in mydict.items())
MestreLion
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