Open popup at clicked position

Question

Hi,

I have done a popup which is by default hidden and opened whenever a click is triggered on window. Popup must be shown at wherever the event is triggered.But there are some constraints:

Popup must be shown at current visible window.Meaning,If I clicked at right most part of the window then,popup must be shown to right side of the clicked position to avoid scrolling.
If window has scrolling, irrespective of scrolling it should be shown at visible part of the window.

Everything is working fine in my present code except in the case,if window has scrolling. If scroll down and click on the middle of the window, popup is displayed at out of the window current display area.........................

<!DOCTYPE HTML PUBLIC>
<html>
 <head>
  <script type="text/javascript" src="http://code.jquery.com/jquery-1.7.1.js"></script>
  <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.js"></script>
 <style>
   div{
     border:1px solid;
     background:#ff9999;
     width:500px;
     height:500px;
     display:none;
     position:absolute;
   }
 </style>
  <script>
   var mouseX,mouseY,windowWidth,windowHeight;
   var  popupLeft,popupTop;
 $(document).ready(function(){

   $(document).mousemove(function(e){
           mouseX = e.pageX;
           mouseY = e.pageY;
           //To Get the relative position
           if( this.offsetLeft !=undefined)
             mouseX = e.pageX - this.offsetLeft;
           if( this.offsetTop != undefined)
             mouseY = e.pageY; - this.offsetTop;

           if(mouseX < 0)
                mouseX =0;
           if(mouseY < 0)
               mouseY = 0;

           windowWidth  = $(window).width();
           windowHeight = $(window).height();
   });

     $('html').click(function(){
       $('div').show();
      var popupWidth  = $('div').outerWidth();
      var popupHeight =  $('div').outerHeight();

      if(mouseX+popupWidth > windowWidth)
        popupLeft = mouseX-popupWidth;
      else
       popupLeft = mouseX;

      if(mouseY+popupHeight > windowHeight)
        popupTop = mouseY-popupHeight;
      else
        popupTop = mouseY; 
      if(popupLeft < 0)
          popupLeft = 0;
      if(popupTop < 0)
          popupTop = 0;

      $('div').offset({top:popupTop,left:popupLeft});
     });
 });
  </script>
 </head>

 <body>
        <br/><br/><br/>  <br/><br/><br/><br/> <br/><br/> <br/>   <br/>   <br/>   <br/>   <br/>   <br/> 
        <br/><br/> <br/> <br/> <br/>    <br/><br/><br/> <br/><br/>  <br/>   <br/><br/><br/><br/><br/><br/>
        <br/><br/><br/><br/><br/><br/><br/><br/>    

        <div>
         s dflasld fsadf
         sdfas dfsadf
        </div>

</body>

</html>

Can you please check it.......

panda · Answer 1 · 2012-05-08T06:32:39.433

8

maybe you can load the windowW/H in the init time and out of your function.

The concept is use the mouseY-scrolled high, because the mouseY is related to the body.so use this:

 $(document).ready(function(){

     $('html').click(function(e){
      mouseX=e.pageX;
      mouseY=e.pageY;
      var bodyTop = document.documentElement.scrollTop + document.body.scrollTop;
      ..
      //window.outerWidth is not working in IE
      var windowWidth  = $(window).outerWidth();
      var windowHeight = $(window).outerHeight();
      ..
      if(mouseY-bodyTop+popupHeight > windowHeight)
        ...
        ...
      //set the position first. remove the position attr in css   
      $('div').css({position:"absolute",top:popupTop,left:popupLeft});
      $('div').show();
     });
 });

edited May 08 '12 at 06:32

answered May 08 '12 at 05:23

panda

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35

Have you checked it in IE9?...K, you may add some more BR tags to get scrolling...Please check it adding some br tags. – Rama Rao M May 08 '12 at 05:30
The problem still persists.When I scroll down and click on 300px down to the window top, some top part of the popup top hidden behind the scrolling.That is what actually should be avoided. – Rama Rao M May 08 '12 at 06:15
it may work now. the reason of jumping was that you show the div first. also, offset seems not work in IE, use css instead. Also window.outerWidth is not working in IE – panda May 08 '12 at 06:34
oh, remove the mousemove event – panda May 08 '12 at 06:35
you need to remove something from your origin file, make sure variables is unique. – panda May 08 '12 at 07:14

score 8 · Accepted Answer · answered May 09 '12 at 05:32

Finally, I could done it by having small changes...This is the piece of code that works fine...

<html>
 <head>
  <script type="text/javascript" src="http://code.jquery.com/jquery-1.7.1.js"></script>
  <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.js"></script>
 <style>
   div{
     border:1px solid;
     background:#ff9999;
     width:500px;
     height:500px;
     display:none;
     position:absolute;
   }
 </style>
  <script>
   var mouseX,mouseY,windowWidth,windowHeight;
   var  popupLeft,popupTop;
 $(document).ready(function(){

   $(document).mousemove(function(e){
           mouseX = e.pageX;
           mouseY = e.pageY;
           //To Get the relative position
           if( this.offsetLeft !=undefined)
             mouseX = e.pageX - this.offsetLeft;
           if( this.offsetTop != undefined)
             mouseY = e.pageY; - this.offsetTop;

           if(mouseX < 0)
                mouseX =0;
           if(mouseY < 0)
               mouseY = 0;

           windowWidth  = $(window).width()+$(window).scrollLeft();
           windowHeight = $(window).height()+$(window).scrollTop();
   });

     $('html').click(function(){
       $('div').show();
      var popupWidth  = $('div').outerWidth();
      var popupHeight =  $('div').outerHeight();

      if(mouseX+popupWidth > windowWidth)
        popupLeft = mouseX-popupWidth;
      else
       popupLeft = mouseX;

      if(mouseY+popupHeight > windowHeight)
        popupTop = mouseY-popupHeight;
      else
        popupTop = mouseY; 

    if( popupLeft < $(window).scrollLeft()){
     popupLeft = $(window).scrollLeft();
    }

    if( popupTop < $(window).scrollTop()){
     popupTop = $(window).scrollTop();
    }

     if(popupLeft < 0 || popupLeft == undefined)
           popupLeft = 0;
      if(popupTop < 0 || popupTop == undefined)
           popupTop = 0;

      $('div').offset({top:popupTop,left:popupLeft});
     });
 });
  </script>
 </head>

 <body>
        <br/><br/><br/>  <br/><br/><br/><br/> <br/><br/> <br/>   <br/>   <br/>   <br/>   <br/>   <br/> 
        <br/><br/> <br/> <br/> <br/>    <br/><br/><br/> <br/><br/>  <br/>   <br/><br/><br/><br/><br/><br/>
        <br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/>        

        <div>
         s dflasld fsadf
         sdfas dfsadf
        </div>

</body>

</html>

Open popup at clicked position

2 Answers2

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