How to remove the decimal part from a float number that contains .0 in java

Question

I just want to remove the fractional part of a float number that contains .0. All other numbers are acceptable.. For example :

  I/P: 1.0, 2.2, 88.0, 3.56666, 4.1, 45.00 , 99.560
  O/P: 1 ,  2.2, 88,   3.567,   4.1, 45 ,    99.560

Is there any method available to do that other than "comparing number with ".0" and taking substring" ?

EDIT : I don't want ACTING FLOAT NUMBERs (like 1.0, 2.0 is nothing but 1 2 right?)

I feel my question is little confusing...
Here is my clarification: I just want to display a series of floating point numbers to the user. If the fractional part of a number is zero, then display only the integer part, otherwise display the number as it is. I hope it's clear now..

"Comparing number with ''.0'' and taking substring" won't convert "45.00" to "45". Do you want to strip an arbitrary number of zeroes from the end? — Mike Samuel, May 08 '12 at 10:15
Have a look at this : http://stackoverflow.com/questions/703396/how-to-nicely-format-floating-types-to-string — Kazekage Gaara, May 08 '12 at 10:22
Do you have to keep the trailing 0 on '99.560' or would '99.56' be OK? — NickT, May 08 '12 at 10:49
Post some source code. Your question is meaningless without it. — user207421, May 08 '12 at 10:51
@ NickT it doesnt matter i only integer in integer format. i dont want ACTING FLOAT NUMBER (like 1.0, 2.0 is nothing but 1 2 right?) — vnshetty, May 08 '12 at 10:52
@ EJP i dont want ACTING FLOAT NUMBERs (like 1.0, 2.0 is nothing but 1 2 right?) — vnshetty, May 08 '12 at 10:53
I don't understand your comment. What I meant was that for all the i/ps and required o/ps you have listed, then IF for an i/p of 99.560 an o/p of 99.56 was acceptable, then a simple NumberFormat formatter = new DecimalFormat("###.###"), would give you what you require. (all other o/ps would be as you have listed them) — NickT, May 08 '12 at 10:58
@vnshetty: In what way does your statement constitute posting source code? — user207421, May 08 '12 at 11:05

amalBit · Answer 1 · 2017-02-06T12:53:35.323

18

If android gives you lemons. Dont throw it.

YourFormatedStringNumber = NumberFormat.getInstance().format(myNumber);

makes -> "12.50" to "12.50"  and "12.00" to "12"

More here in doc.

edited Feb 06 '17 at 12:53

answered Jul 18 '15 at 19:45

amalBit

12,041
6
77
94

1

This is exactly what I want to do ! Fantastic – Mo Zaatar Apr 24 '17 at 08:02

score 15 · Accepted Answer · answered May 08 '12 at 10:16

15

You could use a regular expression such as this: \\.0+$. If there are only 0's after the decimal point this regular expression will yield true.

Another thing you could do is something like so:

float x = 12.5;
float result = x - (int)x;
if (result != 0)
{
    //If the value of `result` is not equal to zero, then, you have a decimal portion which is not equal to 0.
}

answered May 08 '12 at 10:16

npinti

51,780
5
72
96

thanks for that, fast and efficient ^^ Under Android i did Float remains = floatval - FloatMath.floor(floatval); – Darkendorf Nov 08 '12 at 07:48

score 13 · Answer 3 · answered Jul 16 '15 at 09:21

13

Try:

String.format("%.0f",value);

answered Jul 16 '15 at 09:21

Sam

446
7
17

Did not help. It still keeps the zeros. – Azizjon Kholmatov Aug 22 '19 at 04:57

score 3 · Answer 4 · answered Jan 27 '20 at 10:03

3

I can't comment yet so just a heads up. number value needs to be a double for it to work.

String.format("%.0f", number)

answered Jan 27 '20 at 10:03

Mr. Disability

799
1
10
19

Roman K · Answer 5 · 2019-12-29T09:20:13.407

2

try NumberFormat or even DecimalFormat:

If you want to not show a decimal point where there might be no digits after the decimal point, use setDecimalSeparatorAlwaysShown.

edited Dec 29 '19 at 09:20

answered May 08 '12 at 10:15

Roman K

3,309
1
33
49

Jaco Van Niekerk · Answer 6 · 2012-05-09T06:03:19.493

0

Well, technically the display part is text, so you could do it with regular expression. If the number matches then use groups to extract the correct part. (I'll update the post with a solution later.)

Alternatively, you could simply go:

if ((int)Math.round(number) == number) {
   System.out.println((int) number)  
} else {
   System.out.println(number)  
}

or even:

System.out.println((int) Math.round(number) == number ? 
    String.valueOf((int) number) : String.valueOf(number));

careful, the String.valueOf() is required, as this does not work. The System.out.println(double) will always get executed, i.e. the below does not work:

System.out.println((int)Math.round(number) == number ? (int) number : number);

edited May 09 '12 at 06:03

answered May 08 '12 at 10:16

Jaco Van Niekerk

4,180
2
21
48

-1 your final print statement (with the tertiary operator) doesn't work because `println(double)` will always be invoked. – dogbane May 08 '12 at 10:29
I don't understand... how do you get that? – Jaco Van Niekerk May 08 '12 at 11:19

score 0 · Answer 7 · answered Jun 23 '17 at 03:20

0

try casting int before the float number

answered Jun 23 '17 at 03:20

Nizam Ahmed

1
7

Please See this first before answering. [link](https://stackoverflow.com/help/how-to-answer) – always-a-learner Jun 23 '17 at 03:41

score 0 · Answer 8 · answered Feb 23 '21 at 18:16

I've created this extension method. if amount contains decimal(40.01) it will show decimal other wise it will show only amount(40.00)

input 2000.43, Result = 2,000.43

input 2000.00, Result = 2,000

 fun Double.FormattedAmount(): String {

    val otherSymbols = DecimalFormatSymbols(Locale.US)
    val decimalFormat = DecimalFormat("#,###,###.##", otherSymbols)
    return decimalFormat.format(this).toString()

 }

score 0 · Answer 9 · answered Apr 06 '22 at 09:26

0

Very simple for kotlin

float number = 12.5
number.toInt()

answered Apr 06 '22 at 09:26

donmj

379
7
13

How to remove the decimal part from a float number that contains .0 in java

9 Answers9

Linked