C++ : value from variable as variable

Question

how to print variable from value of other variable in c++ i'm just new in c++.

in php we can make/print a variable by the value of other variable. like this.

$example = 'foo';
$foo = 'abc';
echo ${$example}; // the output will 'abc'

how can i solve this in c++?

C++ doesn't have this feature (which is reflection): http://stackoverflow.com/questions/2911442/access-variable-value-using-string-representing-variables-name-in-c — wkl, May 10 '12 at 04:18

score 3 · Answer 1 · answered May 10 '12 at 04:18

3

You cannot.

The only way to emulate this (well sort of) is to use a map

answered May 10 '12 at 04:18

Ed Heal

score 1 · Answer 2 · answered May 10 '12 at 04:17

1

Getting a variable/member by its name is called reflection/introspection.

There is no reflection mechanism in C++, and basically you can't do that.

answered May 10 '12 at 04:17

MByD

score 0 · Accepted Answer · answered May 10 '12 at 04:46

Looking at it another way, it's just indirection, which C++ uses extensively. An analogous example in C++ might be...

using namespace std;
string foo = "abc";
string* example = &foo;
cout << *example << endl;  // The output will 'abc'

...or using a reference instead of a pointer...

using namespace std;
string foo = "abc";
string& example = foo;
cout << example << endl;  // The output will 'abc'

3 Answers3