I have an hbm file which is as below:
<?xml version="1.0" encoding="utf-8" ?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping auto-import="true" default-lazy="false">
<class name="com.saman.entity.hibernate.EmployeeEntity"
table="Employee" optimistic-lock="version">
<id name="id">
<column name="Id" sql-type="bigint"/>
<generator class="native"/>
</id>
<timestamp name="version" source="db"/>
<property name="firstName">
<column name="FirstName" sql-type="nvarchar(300)"/>
</property>
<property name="lastName">
<column name="LastName" sql-type="nvarchar(300)"/>
</property>
<property name="employeeType">
<column name="EmployeeType" sql-type="nvarchar(300)"/>
</property>
<set name="shifts" table="Shifts" inverse="true" lazy="true" fetch="select">
<key>
<column name="Id" not-null="true"/>
</key>
<one-to-many class="com.saman.entity.hibernate.ShiftEntity"/>
</set>
</class>
</hibernate-mapping>
now I wanted if I add an employee and persist it, if then I add another employee with the previous information, my system raises an exception and tell me that I have another employee in the database with that informations.
does hibernate give me this option?