c# 7za.exe process status

Question

I'm running a 7za.exe process to 7zip a file like this:

ProcessStartInfo proc = new ProcessStartInfo();
proc.FileName = zip_Path;
proc.Arguments = "a -t7z ziped.7z file.bak";
proc.RedirectStandardInput = true;
proc.RedirectStandardOutput = true;
proc.UseShellExecute = false;
proc.CreateNoWindow = true;
p = Process.Start(proc); 
while (!p.HasExited)
{   
    res = p.StandardOutput.ReadLine();
    texto += "\n" + res;
}
 MessageBox.Show(texto + "\n" + "ErrorCode:" + p.ExitCode);
 p.Close();

This works fine, but when I run the 7za.exe on the console manually, I can see the zipping progress. Is there any way to output it in real time on my application?

score 2 · Answer 1 · edited May 23 '17 at 11:46

I know this is an old question but I found the answer here https://stackoverflow.com/a/4291965/4050735

Code sample from answer:

var proc = new Process {
StartInfo = new ProcessStartInfo {
    FileName = "program.exe",
    Arguments = "command line arguments to your executable",
    UseShellExecute = false,
    RedirectStandardOutput = true,
    CreateNoWindow = true
}

proc.Start();
while (!proc.StandardOutput.EndOfStream) {
    string line = proc.StandardOutput.ReadLine();
    // do something with line
}

I found that this returned every line you would normally see in the console such as each file that was compressed one at a time.

score 2 · Answer 2 · edited Mar 23 '17 at 12:26

Hej, I was having the very same problem today. So here to all those searching for an answer and hitting this site (I suppose as you posted the question in 2014 you'll have no use for this information any more) here is how I got around the problem:

The core to this is that 7-Zip uses different streams to write to the output and C# only gets one of them. But you can force 7-Zip to use only one stream by using the command-line arguments

-bsp1 -bse1 -bso1

in addition to what else you need. Then just capture the percentage part like this:

private static void CreateZip(string path, string zipFilename, Action<int> onProgress) {
    Regex REX_SevenZipStatus = new Regex(@"(?<p>[0-9]+)%");

    Process p = new Process();
    p.StartInfo.FileName = "7za.exe";
    p.StartInfo.Arguments = string.Format("a -y -r -bsp1 -bse1 -bso1 {0} {1}", 
        zipFilename, path);
    p.StartInfo.UseShellExecute = false;
    p.StartInfo.RedirectStandardOutput = true;

    p.OutputDataReceived += (sender, e) => {
        if (onProgress != null) {
            Match m = REX_SevenZipStatus.Match(e.Data ?? "");
            if (m != null && m.Success) {
                int procent = int.Parse(m.Groups["p"].Value);
                onProgress(procent);
            }
        }
    };

    p.Start();
    p.BeginOutputReadLine();
    p.WaitForExit();
}

This method compresses a folder into a 7-Zip file. You can use the onProgress parameter (called in another thread) to process the status - it will contain the percentage of the status.

@Bhargav why delete that part of the answer? Did this get a NAA flag? — user247702, Mar 23 '17 at 12:27
Yeah, @Stijn, removed the last part as the remaining was a valid answer. — Bhargav Rao, Mar 23 '17 at 12:31

score 0 · Answer 3 · answered May 11 '12 at 13:52

0

Instead of:

proc.CreateNoWindow = true;

try:

proc.WindowStyle = ProcessWindowStyle.Hidden;

answered May 11 '12 at 13:52

Eric

391
1
8

the console is hidding as it should be, but the p.StandardOutput.ReadLine(); is not returning the progress of the compression so i could show in real time the status of the 7za.exe process – Joaolvcm May 11 '12 at 14:02

score 0 · Answer 4 · answered Apr 01 '14 at 01:13

Depending on how it interacts with the console ReadLine() may not be sufficient as it will only return if a new line character is output.

7za.exe may be be manipulating the current line to display progress in which case you should be able to use Read().

If you want a better insight into what is going on with the compression you can look into using the LZMA C# SDK - check out SevenZipSharp.

c# 7za.exe process status

4 Answers4