I have a list of curse words I want to match against other list to remove matches. I normally use list.remove('entry') on an individual basis, but looping through a list of entries against another list - then removing them has me stumped. Any ideas?
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Using filter:
>>> words = ['there', 'was', 'a', 'ffff', 'time', 'ssss']
>>> curses = set(['ffff', 'ssss'])
>>> filter(lambda x: x not in curses, words)
['there', 'was', 'a', 'time']
>>>
It could also be done with list comprehension:
>>> [x for x in words if x not in curses]
Facundo Casco
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3Making `curses` a list is a bad idea - `in` is O(1) for a set, O(n) for a list. – Hugh Bothwell May 11 '12 at 23:32
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Use sets.
a=set(["cat","dog","budgie"])
b=set(["horse","budgie","donkey"])
a-b
->set(['dog', 'cat'])
Jay M
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What if I already have the lists define? Could I do: a = ['bad_word1', 'bad_word2' ] b = ['a', 'b', 'bad_word1' ] set1 = set(a) set2 = set(b) set1 - set2 a = set1 b = set2 – ewhitt May 11 '12 at 22:50
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notice that sets could mess the order of the words and also would remove duplicate words from your list. Also it should be faster I guess. – Facundo Casco May 11 '12 at 22:56