$object->($string)

Question

I am dealing with an object of a class that I did not write and cannot change.This class has a very large number of attributes. I want to cycle trough about half of these attributes (a select group). I put the names of the nescessary attributes into an array and would like to cycle through them. Is this possible? What is the syntax like?

class B{
   public $foo = 'hi';
   public $bar = 'bye';
   ...etc, etc.
}

$arr = array(1=>'foo', 2=>'bar', ...)
$b = new B();
foreach($arr as $val){
  echo $b->($val); //<-----does not work
}

You need to use curly brackets `{$val}` instead of parentheses... — animuson, May 15 '12 at 19:58
possible duplicate of [Iterate through array and get key and value](http://stackoverflow.com/questions/3753394/iterate-through-array-and-get-key-and-value) — legoscia, Apr 29 '14 at 11:05

score 5 · Answer 1 · answered May 15 '12 at 19:58

Yes you can. see the manual: http://php.net/manual/en/language.variables.variable.php

<?php
class foo {
    var $bar = 'I am bar.';
}

$foo = new foo();
$bar = 'bar';
$baz = array('foo', 'bar', 'baz', 'quux');
echo $foo->$bar . "\n";
echo $foo->$baz[1] . "\n";
?>

The above example will output:

I am bar.
I am bar

score 1 · Answer 2 · answered May 15 '12 at 19:59

1

echo $b->$val;

or method

echo $b->$val(params...);

and u can use one of the reflection functions to get all the methods and members

answered May 15 '12 at 19:59

Itay Moav -Malimovka

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score 1 · Accepted Answer · answered May 15 '12 at 20:01

1

You were close:

$b->$val; //Or...
$b->{$val};

answered May 15 '12 at 20:01

Madara's Ghost

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score 0 · Answer 4 · answered May 15 '12 at 20:00

0

You can loop through each variable like this:

$b= new B();

foreach($b as $var => $value) {
    echo "$var is $value\n";
}

answered May 15 '12 at 20:00

GDP

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$object->($string)

4 Answers4