How to validate mobile phone number entered?

Question

complete = (Button) findViewById(R.id.complete);
complete.setOnClickListener(new View.OnClickListener() {

        String validNumber = "";

    public void onClick(View v){

        validNumber = phoneNumber.getText().toString();

        if (!validNumber.equals("")){

                final String phoneNumPattern = "^(?=.*[0-9]){10,11}$";  
                Pattern pattern = Pattern.compile(phoneNumPattern);
                Matcher matcher = pattern.matcher(validNumber);     

                 if (matcher.matches() == true){
            Toast.makeText(PhoneNumActivity.this, "Success", Toast.LENGTH_SHORT).show();        
                 }
                 else{
            Toast.makeText(PhoneNumActivity.this, "Failed", Toast.LENGTH_SHORT).show();
                  }
        }
        else{
                 Toast.makeText(PhoneNumActivity.this, "Failed", Toast.LENGTH_SHORT).show();
        }
    }
 });

I am developing an security apps which user needs to enter a valid mobile phone number, I set the pattern above where user can only enter number with min 10 digit and max 11 digit. But it come out an error

java.util.regex.PatternSyntaxException: Syntax error in regexp pattern near index 13:

And one more question, can I set the pattern so that the first two digits of the mobile number is 01xxxxxxxxxx?

Apart from your regex issue, it is maybe worth checking that your pattern will work for any format of phone number accross countries. — assylias, May 16 '12 at 10:32

score 2 · Answer 1 · answered May 16 '12 at 10:38

Use an EditText for the input and give it this xml attribute:

android:inputType="phone"

The user wont be able to put non valid characters inside.

For your pattern of 01 you just have to check if the first 2 chars are "01"

if( phoneNumer.charAt(0)=='0'&&phoneNumber.charAt(1)=='1')

score 0 · Answer 2 · edited May 23 '17 at 12:04

0

Phone number validation can be quite complex, but it looks like this has been discussed before in this thread.

edited May 23 '17 at 12:04

Community

1
1

answered May 16 '12 at 10:36

stuckless

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score 0 · Answer 3 · answered May 16 '12 at 10:37

This method may help you. This method returns false if string contains any non-numeric characters.

public static boolean abcd(String str)
    {
        int x;
        for(int j = 0 ; j < str.length() ; j++)
        {
            x = (int)str.charAt(j);
            if( x < 48 || x > 57 )
            return false;    
        }
        return true;
    }

How to validate mobile phone number entered?

3 Answers3