Open stream from uri

Question

I got an uri (java.net.URI) such as http://www.example.com. How do I open it as a stream in Java?

Do I really have to use the URL class instead?

The problem with URL is that equals and hashcode are blocking operations which does network lookup. Url also seems to be missing a method to normalize a url and convert an relative url to an absolute url. — MTilsted, May 19 '12 at 04:40
["Use `URI` where possible" – Java Puzzlers Episode VI](https://youtu.be/wDN_EYUvUq0?t=9m58s). — MC Emperor, Aug 20 '18 at 13:12

score 16 · Accepted Answer · edited Aug 28 '17 at 14:03

16

You will have to create a new URL object and then open stream on the URL instance. An example is below.

try {

   URL url = uri.toURL(); //get URL from your uri object
   InputStream stream = url.openStream();

} catch (MalformedURLException e) {
   e.printStackTrace();
} catch (URISyntaxException e) {
   e.printStackTrace();
}catch (IOException e) {
   e.printStackTrace();
}

edited Aug 28 '17 at 14:03

azro

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answered May 18 '12 at 18:18

Vijay Shanker Dubey

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8

uri.toURL() is not showing in my android studio project? – Yash Agrawal Sep 14 '16 at 07:02
same uri.toURL() is not showing in my android studio – Wardruna Sep 19 '16 at 13:04
`toURL()` does not work on Android because Android uses `android.net.Uri`, not `java.net.URI` as referenced in this post. For Android [see here](https://stackoverflow.com/a/38568666/559745). – Floern Sep 07 '20 at 13:04

score 6 · Answer 2 · answered May 18 '12 at 18:17

6

URLConnection connection = uri.toURL().openConnection()

Yes, you have to use the URL class in one way or the other.

answered May 18 '12 at 18:17

Jeffrey

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score 5 · Answer 3 · answered Feb 19 '19 at 09:46

5

You should use ContentResolver to obtain InputStream:

InputStream is = getContentResolver().openInputStream(uri);

Code is valid inside Activity object scope.

answered Feb 19 '19 at 09:46

marioc64

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score 3 · Answer 4 · edited Jul 05 '17 at 06:52

3

uri.toURL().openStream() or uri.toURL().openConnection().getInputStream()

edited Jul 05 '17 at 06:52

Hkachhia

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answered May 18 '12 at 18:19

ControlAltDel

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score 0 · Answer 5 · answered May 18 '12 at 18:15

0

You can use URLConnection to read data for given URL. - URLConnection

answered May 18 '12 at 18:15

premnathcs

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11

Open stream from uri

5 Answers5

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