How to convert int[] into List in Java?

Question

How do I convert int[] into List<Integer> in Java?

Of course, I'm interested in any other answer than doing it in a loop, item by item. But if there's no other answer, I'll pick that one as the best to show the fact that this functionality is not part of Java.

Answer 1

Streams

1. In Java 8+ you can make a stream of your int array. Call either Arrays.stream or IntStream.of.
2. Call IntStream#boxed to use boxing conversion from int primitive to Integer objects.
3. Collect into a list using Stream.collect( Collectors.toList() ). Or more simply in Java 16+, call Stream#toList().

Example:

int[] ints = {1,2,3};
List<Integer> list = Arrays.stream(ints).boxed().collect(Collectors.toList());

In Java 16 and later:

List<Integer> list = Arrays.stream(ints).boxed().toList();

Answer 2

There is no shortcut for converting from int[] to List<Integer> as Arrays.asList does not deal with boxing and will just create a List<int[]> which is not what you want. You have to make a utility method.

int[] ints = {1, 2, 3};
List<Integer> intList = new ArrayList<Integer>(ints.length);
for (int i : ints)
{
    intList.add(i);
}

Answer 3

Also from guava libraries... com.google.common.primitives.Ints:

List<Integer> Ints.asList(int...)

Answer 4

Arrays.asList will not work as some of the other answers expect.

This code will not create a list of 10 integers. It will print 1, not 10:

int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
List lst = Arrays.asList(arr);
System.out.println(lst.size());

This will create a list of integers:

List<Integer> lst = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);

If you already have the array of ints, there is not quick way to convert, you're better off with the loop.

On the other hand, if your array has Objects, not primitives in it, Arrays.asList will work:

String str[] = { "Homer", "Marge", "Bart", "Lisa", "Maggie" };
List<String> lst = Arrays.asList(str);

Answer 5

I'll add another answer with a different method; no loop but an anonymous class that will utilize the autoboxing features:

public List<Integer> asList(final int[] is)
{
    return new AbstractList<Integer>() {
            public Integer get(int i) { return is[i]; }
            public int size() { return is.length; }
    };
}

Answer 6

The smallest piece of code would be:

public List<Integer> myWork(int[] array) {
    return Arrays.asList(ArrayUtils.toObject(array));
}

where ArrayUtils comes from commons-lang :)

Answer 7

In Java 8 with stream:

int[] ints = {1, 2, 3};
List<Integer> list = new ArrayList<Integer>();
Collections.addAll(list, Arrays.stream(ints).boxed().toArray(Integer[]::new));

or with Collectors

List<Integer> list =  Arrays.stream(ints).boxed().collect(Collectors.toList());

Answer 8

In Java 8 :

int[] arr = {1,2,3};
IntStream.of(arr).boxed().collect(Collectors.toList());

Answer 9

If you are using java 8, we can use the stream API to convert it into a list.

List<Integer> list = Arrays.stream(arr)     // IntStream 
                                .boxed()        // Stream<Integer>
                                .collect(Collectors.toList());

You can also use the IntStream to convert as well.

List<Integer> list = IntStream.of(arr) // return Intstream
                                    .boxed()        // Stream<Integer>
                                    .collect(Collectors.toList());

There are other external library like guava and apache commons also available convert it.

cheers.

Answer 10

It's also worth checking out this bug report, which was closed with reason "Not a defect" and the following text:

"Autoboxing of entire arrays is not specified behavior, for good reason. It can be prohibitively expensive for large arrays."

Answer 11

int[] arr = { 1, 2, 3, 4, 5 };

List<Integer> list = Arrays.stream(arr)     // IntStream
                            .boxed()        // Stream<Integer>
                            .collect(Collectors.toList());

see this

Answer 12

give a try to this class:

class PrimitiveWrapper<T> extends AbstractList<T> {

    private final T[] data;

    private PrimitiveWrapper(T[] data) {
        this.data = data; // you can clone this array for preventing aliasing
    }

    public static <T> List<T> ofIntegers(int... data) {
        return new PrimitiveWrapper(toBoxedArray(Integer.class, data));
    }

    public static <T> List<T> ofCharacters(char... data) {
        return new PrimitiveWrapper(toBoxedArray(Character.class, data));
    }

    public static <T> List<T> ofDoubles(double... data) {
        return new PrimitiveWrapper(toBoxedArray(Double.class, data));
    }  

    // ditto for byte, float, boolean, long

    private static <T> T[] toBoxedArray(Class<T> boxClass, Object components) {
        final int length = Array.getLength(components);
        Object res = Array.newInstance(boxClass, length);

        for (int i = 0; i < length; i++) {
            Array.set(res, i, Array.get(components, i));
        }

        return (T[]) res;
    }

    @Override
    public T get(int index) {
        return data[index];
    }

    @Override
    public int size() {
        return data.length;
    }
}

testcase:

List<Integer> ints = PrimitiveWrapper.ofIntegers(10, 20);
List<Double> doubles = PrimitiveWrapper.ofDoubles(10, 20);
// etc

Answer 13

The best shot:

    /**
     * Integer modifiable fixed length list of an int array or many int's.
     *
     * @author Daniel De Leon.
     */
    public class IntegerListWrap extends AbstractList<Integer> {
    
        int[] data;
    
        public IntegerListWrap(int... data) {
            this.data = data;
        }
    
        @Override
        public Integer get(int index) {
            return data[index];
        }
    
        @Override
        public Integer set(int index, Integer element) {
            int r = data[index];
            data[index] = element;
            return r;
        }
    
        @Override
        public int size() {
            return data.length;
        }
    }

• Support get and set.
• No memory data duplication.
• No wasting time in loops.

Examples:

int[] intArray = new int[]{1, 2, 3};
List<Integer> integerListWrap = new IntegerListWrap(intArray);
List<Integer> integerListWrap1 = new IntegerListWrap(1, 2, 3);

Answer 14

Here is another possibility, again with Java 8 Streams:

void intArrayToListOfIntegers(int[] arr, List<Integer> list) {
    IntStream.range(0, arr.length).forEach(i -> list.add(arr[i]));
}

Answer 15

What about this:

int[] a = {1,2,3};
Integer[] b = ArrayUtils.toObject(a);
List<Integer> c = Arrays.asList(b);

Answer 16

If you're open to using a third party library, this will work in Eclipse Collections:

int[] a = {1, 2, 3};
List<Integer> integers = IntLists.mutable.with(a).collect(i -> i);
Assert.assertEquals(Lists.mutable.with(1, 2, 3), integers);

Note: I am a committer for Eclipse Collections.

Answer 17

   /* Integer[] to List<Integer> */



        Integer[] intArr = { 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 };
        List<Integer> arrList = new ArrayList<>();
        arrList.addAll(Arrays.asList(intArr));
        System.out.println(arrList);


/* Integer[] to Collection<Integer> */


    Integer[] intArr = { 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 };
    Collection<Integer> c = Arrays.asList(intArr);

Answer 18

Here is a solution:

int[] array = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };

Integer[] iArray = Arrays.stream(array).boxed().toArray(Integer[]::new);
System.out.println(Arrays.toString(iArray));

List<Integer> list = new ArrayList<>();
Collections.addAll(list, iArray);
System.out.println(list);

Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Answer 19

Here is a generic way to convert array to ArrayList

<T> ArrayList<T> toArrayList(Object o, Class<T> type){
    ArrayList<T> objects = new ArrayList<>();
    for (int i = 0; i < Array.getLength(o); i++) {
        //noinspection unchecked
        objects.add((T) Array.get(o, i));
    }
    return objects;
}

Usage

ArrayList<Integer> list = toArrayList(new int[]{1,2,3}, Integer.class);

Answer 20

You could use IntStream of and boxed it to Integer after that sorted using reverseOrder comparator.

List<Integer> listItems = IntStream.of(arrayItems)
                .boxed()
                .sorted(Collections.reverseOrder())
                .collect(Collectors.toList());

This approach has the advantage of being more flexible, as you can use different collectors to create different types of lists (e.g., an ArrayList, a LinkedList, etc.).

Answer 21

Arrays.stream(ints).forEach(list::add);