Restore .bak files

Question

I ran a perl script using

perl -p -i.bak -e "..." *.sh dir/*.sh

This created a copy of every file like

script.sh
script.sh.bak

I now want to restore from the .bak files. How can I do this easily?

score 7 · Accepted Answer · answered May 29 '12 at 08:01

7

for file in *.sh.bak dir/*.sh.bak; do cp "$file" "${file//.bak}"; done

Or you could use mv instead of cp.

answered May 29 '12 at 08:01

Dennis Williamson

Op De Cirkel: Why do you say it won't work? I believe the shell can handle any amount of files as the result of wildcard expansion; it's when you try to pass a long list to another process that `ARG_MAX` could bite you. – tripleee May 29 '12 at 09:22
1

@OpDeCirkel: [`ARG_MAX` doesn't apply to shell builtins](http://stackoverflow.com/questions/6461227/limits-of-length-for-the-output-of-in-bash) – Dennis Williamson May 29 '12 at 12:24
@tripleee: You are correct. See my comment to Op De Cirkel above. – Dennis Williamson May 29 '12 at 12:24
@Dennis Williamson You are right, ARG_MAX does not apply to built-ins....Good to know – Op De Cirkel May 29 '12 at 19:19

score 2 · Answer 2 · answered May 29 '12 at 08:20

2

find -name '*.bak'|sed 's:.bak$::'|xargs -n 1 -I % cp %.bak %

answered May 29 '12 at 08:20

Op De Cirkel

2

That won't work if you have filenames which include newlines. – Dennis Williamson May 29 '12 at 12:16

score 0 · Answer 3 · answered Aug 03 '13 at 13:21

Thanks for this fix.

I've been using a combo the code below to fix an 'eval(base64_decode' in Joomla sites.

find: grep -lr --include=*.php "eval(base64_decode" ./

remove: grep -lr --include=.php "eval(base64_decode" ./ | xargs sed -i.bak 's/eval(base64_decode[^;];/\n/g'

undo: find -name '*.bak'|sed 's:.bak$::'|xargs -n 1 -I % cp %.bak %

3 Answers3