Is an object function executed with each method call?

Question

In this:

somefunction = function() {

    somefunction.method = function() {
         //stuff
    }
//other stuff
}

Is somefunction executed everytime somefunction.method is?

Answer 1

No, somefunction is executed when you have any of these lines:

somefunction()
somefunction.call()
somefunction.apply()
new somefunction;

somefunction.method() will only execute somefunction.method, but that will have access to variables in the scope of somefunction (as well as its own local variables and all global variables of course).

Answer 2

Not inherently (unless it is explicitly invoked in the "other stuff"). It is evaluated, but that is only CPU time and not enough to matter.

Answer 3

No. However you are creating a new closure each time somefunction is called. If somefunction relies on any variables outside of its scope, then the somefunction.method may change depending on when somefunction is called, thus creating a race condition (never fun to debug).

This is probably not the right way to approach the problem.

Consider

somefunction = function() {
  // constructor
}


somefunction.prototype.method = function() {
  //stuff
}