Trying to find a value doesnt work with a variable

Question

IDK if I'm just overlooking something but i can get this to work:

var scu = 0291285;
$('input[value=scu]').val('changed');

nothing happens, but when i try:

$('input[value=0291285]').val('changed');

the input with a value of 0291285 changes. will this method not take a var, and if so is there a work around for this?

possible duplicate of http://stackoverflow.com/questions/5891840/how-to-use-javascript-variables-in-jquery-selectors — Kyle Macey, Jun 06 '12 at 22:33

score 2 · Answer 1 · answered Jun 05 '12 at 23:24

2

jQuery does not know about the scu local variable that you have declared. It thinks you want to look for an <input> whose value is the string literal 'scu'. You want this:

$('input[value=' + scu.toString() + ']').val('changed');

answered Jun 05 '12 at 23:24

univerio

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Doh, I did that but didn't do .toString. Thanks. – user1114060 Jun 05 '12 at 23:25
`toString()` doesn't do anything here. when you concatenate to a string the variable is automatically converted to a string. – Paul Jun 05 '12 at 23:28
You are right, @PaulP.R.O., it appears his problem was the leading 0. – univerio Jun 05 '12 at 23:29

score 1 · Answer 2 · answered Jun 05 '12 at 23:26

1

You need stu to be a string to keep your leading 0:

var scu = '0291285';

Then you need to use the concatenation operator (+) in your selector, to have the value that was in your variable be used:

$('input[value=' + scu + ']').val('changed');

answered Jun 05 '12 at 23:26

Paul

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score 0 · Answer 3 · answered Jun 05 '12 at 23:24

0

$('input[value=' + scu + ']').val('changed');

answered Jun 05 '12 at 23:24

JMC

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Trying to find a value doesnt work with a variable

3 Answers3