I would like to SELECT * FROM table
where the first column is equal to a variable. It supposed that I don't know the column name.
I know I can do something like
SELECT * FROM table WHERE column_id = 1
But I can't compare the data.
How can I do that?
I found some solution with T-SQL but it doesn't interest me.
To be more accurate :
I'm developing an administration panel in my website where the "super" admin can directly modify the database. For that I can select a table and edit this table. But to do that, I'm using an only PHP script which showing all tables, we can select one and the script show all rows in the selected table. After that you select a row and you are redirected to a page where the problem is. This page can receive any table with only one row, so I want to SELECT
the data contained in this row.
Images to understand:
The first one shows the tables.
The second shows the rows of a selected table.
The third shows (normally) the data of 1 row but in this picture we can see data of many rows.
selecto http://imageshack.us/g/135/selecto.png
I found a solution :
Try to explain: First : I selected all form the specific table which was posted
$query="SELECT * FROM ".$_POST['table']."";
$result=mysql_query($query);
Second: I attributed to a variable the column name (which I didn't know)
while($fields=mysql_fetch_array($result))
{
$col = mysql_field_name($result,0);
$nb++;
}
Third: I selected data from the table where $col = id
of the row
$sql = "SELECT * FROM ".$_POST['table']." WHERE ".$col."=".$_GET['idRow']."";
$result1=mysql_query($sql);