How to break parsed result?

Question

I m performing JSON parsing. In return i m getting the result something like this:

{"login":"FALSE","userid":"Please enter correct Email Address"}

I want to retain the userid: message into some variable, so that i can perform functions on the basis of userid itself.

Suggestion please.

Thanks

some 'literature': http://en.wikipedia.org/wiki/JSON, this answer might help you: http://stackoverflow.com/a/5813223/653513 — Rok Jarc, Jun 07 '12 at 15:19
If you're o.k. with supporting iOS >= 5.0 then you'll probably be best off using [NSJSONSerialization Class](http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSJSONSerialization_Class/Reference/Reference.html) — Rok Jarc, Jun 07 '12 at 15:39
my app will be dealing with iOS >= 5 only....i m quite confused about taking that userid: "message" into some string.not able to get it — FirstTimer, Jun 07 '12 at 15:47

skram · Accepted Answer · 2012-06-07T16:08:44.877

0

You can try with a framework such as this,https://github.com/stig/json-framework

Example usage would be, assuming userId is declared in your header file.

SBJSON *parser = [[SBJSON alloc] init];

NSArray *statuses = [parser objectWithString:json_string error:nil];

userId = [statuses valueForKey:@"userid"];

Now userId retains the value for the json value for userid from the json string

UPDATE: If you're only supporting iOS >= 5.0 I would suggest the built in NSJSONSerialization class. If this is the case, your code will look more like this..

NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];

NSMutableArray *jsonList = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:nil];

userId = [jsonList valueForKey:@"userid"];

NSLog(@"userid: %@", userId); // will print "Please enter correct Email Address"

Hope this helps !

edited Jun 07 '12 at 16:08

answered Jun 07 '12 at 15:47

skram

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Do i need to include anything for adding the above lines? – FirstTimer Jun 07 '12 at 15:58
Yes. The JSON Framework I mentioned above.. – skram Jun 07 '12 at 16:02
Updated my answer to include solution for iOS >= 5.0. – skram Jun 07 '12 at 16:10
@skram: SBJSON is an excellent JSON framework - I use it in iOS 5 apps because I, personally, do not like the built-in framework. – Evan Mulawski Jun 07 '12 at 16:25
My Server is down, so i m not able to test it for few more hours....i m gonna check upvote, bcoz, i guess this will work for me. – FirstTimer Jun 08 '12 at 10:37
Great, if and or when you feel it is the `answer`. Check it off as such! Good Luck – skram Jun 08 '12 at 10:42
Superb...that worked smoothly....Thanks Skram – FirstTimer Jun 12 '12 at 15:36

How to break parsed result?

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