i have a user control in which i want to pass page url to my XSL sheet and apply it to my XML file . as a result of it should produce some HTML output. Please explain how to do this?
xml file name: myXml.xml
Xsl file name: mwXsl.xsl
Parameter to be passed by usercontrol(.cs) file: url of parent page.
i've defined XSL stylesheet. All i need to pass the argument to that file. in usercontrol(ascx) file i have this code
<asp:Xml ID="BControl" runat="server" DocumentSource="/wsitemap.sitemap" TransformSource="/Bread.xslt"></asp:Xml>
where wsitemap.sitemap is a XML file. if my XSLT get the argument the above code will be able to produce the desired output. so i need c# code for that.
in usercontrol (.cs file) i have :
public static string Transform(string xml, string xsl, XsltArgumentList argsList)
{
XDocument selectedXml = XDocument.Parse(xml);
XslCompiledTransform xmlTransform = new XslCompiledTransform();
StringBuilder htmlOutput = new StringBuilder();
XmlWriter writer = XmlWriter.Create(htmlOutput);
xmlTransform.Load(new XmlTextReader(new StringReader(xsl)));
xmlTransform.Transform(selectedXml.CreateReader(), argsList, writer);
return htmlOutput.ToString();
}
protected void Page_Load(object sender, EventArgs e)
{
string curPageId = Page.Request.Url.AbsoluteUri;
XsltArgumentList xslArgs = new XsltArgumentList();
xslArgs.AddParam("curPage", "", curPageId);
string output=Transform("wsitemap.sitemap","bread.xslt",xslArgs);
Response.Clear(); Response.Write(output);
}
but this code is not working , any other approach plz tell me
