I have been reading The Seasoned Schemer and i came across this definition of the length function
(define length
(let ((h (lambda (l) 0)))
(set! h (L (lambda (arg) (h arg))))
h))
Later they say :
What is the value of (L (lambda (arg) (h arg)))? It is the function
(lambda (l)
(cond ((null? l) 0)
(else (add1 ((lambda (arg) (h arg)) (cdr l))))))
I don't think I comprehend this fully. I guess we are supposed to define L ourselves as an excercise. I wrote a definition of L within the definition of length using letrec. Here is what I wrote:
(define length
(let ((h (lambda (l) 0)))
(letrec ((L
(lambda (f)
(letrec ((LR
(lambda (l)
(cond ((null? l) 0)
(else
(+ 1 (LR (cdr l))))))))
LR))))
(set! h (L (lambda (arg) (h arg))))
h)))
So, L takes a function as its argument and returns as value another function that takes a list as its argument and performs a recursion on a list. Am i correct or hopelessly wrong in my interpretation? Anyway the definition works
(length (list 1 2 3 4)) => 4