Is there a ruby equivalent for rmul?

Question

Is there a ruby equivelent for __rmul__ in ruby? I can't seem to find anything about this.

score 2 · Answer 1 · answered Jun 20 '12 at 16:15

2

not sure about py, but is overloading operator * what you want?

if then, a method * will be fine.

a=Object.new
def a.*(rhs); rhs+2;end

a*2 #=> 4

answered Jun 20 '12 at 16:15

Jokester

2

rmul is slightly different, it is because you can have like 2*object OR object*2 I need somethign that runs on 2*object not object*2 – KatGaea Jun 20 '12 at 16:16
in ruby, `2*object` is `like 2.*(object)`, and `object*2` is `object.*(2)`. so there is some difference, but not that different – Jokester Jun 20 '12 at 16:23
What would it do if instead of 2, it was some other object, also with an overloaded * ? – KatGaea Jun 20 '12 at 16:28
to be more general, `a.*(b)` for `a*b` then. – Jokester Jun 20 '12 at 16:34
I have posted the answer that seems to work fine for me now, but thankyou very much for the answer – KatGaea Jun 20 '12 at 16:35
glad if it helped maybe a little :) – Jokester Jun 20 '12 at 16:38

score 0 · Accepted Answer · answered Jun 20 '12 at 16:20

0

Looking into things further, it seems the equivelent for rmul is to add

def coerce(other)
    return self, other
end

then have the usual * overloaded handle other types too with is_a?

answered Jun 20 '12 at 16:20

KatGaea

score 0 · Answer 3 · edited May 23 '17 at 12:14

0

Check out this discussion here about coerce in Ruby:

edited May 23 '17 at 12:14

Community

answered Jun 20 '12 at 17:26

robbrit

3 Answers3