Javascript split to split string in 2 parts irrespective of number of spit characters present in string

Question

I want to split a string in Javascript using split function into 2 parts.

For Example i have string:

str='123&345&678&910'

If i use the javascripts split, it split it into 4 parts. But i need it to be in 2 parts only considering the first '&' which it encounters.

As we have in Perl split, if i use like:

($fir, $sec) = split(/&/,str,2)

it split's str into 2 parts, but javascript only gives me:

str.split(/&/, 2);
fir=123
sec=345

i want sec to be:

sec=345&678&910

How can i do it in Javascript.

@ajax333221. It's a good question! Mentioning other language syntax doesn't make it a bad question nor a translation question. — gdoron, Jun 22 '12 at 07:03
Use `indexOf` to get the index of the first `&`. Then use the `substring` function to extract both parts. But it's impossible to be blocked by this if you google "javascript string functions". — Denys Séguret, Jun 22 '12 at 07:04
@gdoron didn't say it wasn't, I just feel he could attempt to do a little more himself. Remember, SO is one of the last options — ajax333221, Jun 22 '12 at 07:05
@ajax333221. How do you know he didn't try enough? Crystal ball? and **who said SO is the last option?!** — gdoron, Jun 22 '12 at 07:06
possible duplicate of [split string only on first instance of specified character](http://stackoverflow.com/questions/4607745/split-string-only-on-first-instance-of-specified-character) — Yoshi, Jun 22 '12 at 07:07
@ajax333221: i tried, then after i asked SO. I think SO as always the best option to get if i am not able to :) — kailash19, Jun 22 '12 at 07:12

score 6 · Answer 1 · edited May 23 '17 at 12:19

6

var subStr = string.substring(string.indexOf('&') + 1);

View this similar question for other answers:

split string only on first instance of specified character

edited May 23 '17 at 12:19

Community

1
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answered Jun 22 '12 at 07:04

infojolt

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score 4 · Accepted Answer · answered Jun 22 '12 at 07:06

4

You can use match instead of split:

str='123&345&678&910';
splited = str.match(/^([^&]*?)&(.*)$/);
splited.shift();
console.log(splited);

output:

["123", "345&678&910"]

answered Jun 22 '12 at 07:06

core1024

1,882
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Florian Margaine · Answer 3 · 2012-06-22T07:26:11.573

3

You can remain on the split part by using the following trick:

var str='123&345&678&910',
    splitted = str.split( '&' ),
    // shift() removes the first item and returns it
    first = splitted.shift();

console.log( first ); // "123"
console.log( splitted.join( '&' ) ); // "345&678&910"

edited Jun 22 '12 at 07:26

answered Jun 22 '12 at 07:10

Florian Margaine

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score 1 · Answer 4 · answered Jun 22 '12 at 07:35

I wrote this function:

function splitter(mystring, mysplitter) {
    var myreturn = [],
        myindexplusone = mystring.indexOf(mysplitter) + 1;

    if (myindexplusone) {
        myreturn[0] = mystring.split(mysplitter, 1)[0];
        myreturn[1] = mystring.substring(myindexplusone);
    }

    return myreturn;
}

var str = splitter("hello-world-this-is-a-test", "-");

console.log(str.join("<br>"));
//hello
//world-this-is-a-test

The output will be either an empty array (not match) or an array with 2 elements (before the split and everything after)

Demo

abuduba · Answer 5 · 2012-06-22T07:58:13.627

I have that:

var str='123&345&678&910';
str.split('&',1).concat( str.split('&').slice(1).join('&') );
//["123", "345&678&910"]



str.split('&',2).concat( str.split('&').slice(2).join('&') );
//["123", "345", "678&910"];

for convenience:

String.prototype.mySplit = function( sep, chunks) {
   chunks = chunks|=0 &&chunks>0?chunks-1:0;
   return this.split( sep, chunks )
              .concat( 
                  chunks?this.split( sep ).slice( chunks ).join( sep ):[]
               );
}

Oluwatobi Samuel Omisakin · Answer 6 · 2016-09-26T09:57:49.993

What about the use of split() and replace()?:

Given we have that string str='123&345&678&910' We can do

    var first = str.split("&",1); //gets the first word
    var second = str.replace(first[0]+"&", ""); //removes the first word and the ampersand

Please note that split() returns an array that is why getting the index with first[0] is recommended, however, without getting the index, it still worked as needed i.e first+"&".

Feel free to replace the "&" with the string you need to split with.

Hope this helps :)

Javascript split to split string in 2 parts irrespective of number of spit characters present in string

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